- #36
ulissess
- 36
- 0
oh yes, sorry ... (-∞,-1] when x is in [0,0.5).. so my z has values in (-∞, -1] U [z,∞) ... z=1 if y=0 .
So i can integrate my PDF in those intervals, in (-1,1) instead my PDF is zero because i haven't my function in that interval. All right?
Slowly I'm coming near the solution, thank you !
So i can integrate my PDF in those intervals, in (-1,1) instead my PDF is zero because i haven't my function in that interval. All right?
Slowly I'm coming near the solution, thank you !
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