- #1
Jahnavi
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Homework Statement
Homework Equations
The Attempt at a Solution
The current will decrease , as a result an EMF will be induced in the cylinder .
The EMF induced E = -dΦ/dt
I am assuming magnetic field through the cylinder to be same as that at the center of the a current carrying coil which is given by μ0i/2r .
E = -μ0πrdi/(2dt)
I tried to calculate equivalent resistance .
I think we can consider thin cylinder material as a thin sheet of breadth 'l' , length '2πr' and thickness 'd' .
It can be divided into thin wires of length '2πr' , width dx and thickness 'd'
Current is flowing across the breadth .
Consider a very thin section of wire of width dx at a distance x across the breadth from one end .
All these thin wires are in parallel .
Their equivalent resistance turns out to be ρ2πr/ld .
So , the resistance across which the current is flowing is R = ρ2πr/ld .
The current equation would be iR + E = 0 .
iR - μ0πrdi/(2dt) = 0
ρ2πri/ld - μ0πrdi/(2dt) = 0
Is the equation correct ?
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