Current in a Resistor-Capacitor Circuit with -5V EMF

[swechan02]

If there is a circuit with--Emf -5V and one 5ohm resistor and one 20 F capacitor, what is the current of the circuit?
Will there be any effects on current because of capacitor?

 

[ZapperZ]

Please note these THREE points:

1. You posted in the wrong section of PF. Did you miss the Homework Help section at the very TOP of the PF list?

2. You multiple post this in the classical physics section. This is a no-no. You may want to read PF's guildelines before you proceed.

3. You should not expect anyone to do your work for you. Please read the Sticky in the Homework help section and note that you should, at the very least, show what you have attempted to do so that we know where we should start in presented to you an explanation.

Zz.

 

[sir-pinski]

The current in a resistor-capacitor circuit with a -5V EMF can be calculated using Ohm's Law (I = V/R) and the formula for capacitive reactance (Xc = 1/(2*pi*f*C)). In this case, the frequency (f) is not given, so we cannot calculate the capacitive reactance. Therefore, we cannot determine the current without additional information.

However, we do know that the capacitor will have an effect on the circuit. When the circuit is first connected, the capacitor will act as an open circuit and no current will flow. As the capacitor charges, the current will gradually increase until it reaches its maximum value determined by the resistance and capacitance values.

Once the capacitor is fully charged, the current will decrease to zero again. This cycle will continue as long as the circuit remains connected and the EMF is maintained. Therefore, the presence of the capacitor will have a significant effect on the current in the circuit.

In summary, without the frequency information, we cannot determine the exact current in this circuit, but we can conclude that the capacitor will have a significant impact on the current behavior.