Current on Parallel Conducting Wires

In summary, the student is struggling with homework and needs help understanding the equations and how to find the fields.
  • #1
aglo6509
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0

Homework Statement



Two very long, straight, parallel wires carry currents that are directed perpendicular to the page as shown in Figure P30.9. Wire 1 carries a current I1 into the page (in the -z direction) and passes through the x-axis at x = +a. Wire 2 passes through the x-axis at x = -2a and carries an unknown current I2. The total magnetic field at the origin due to the current-carrying wires has the magnitude 2µ0I1 / ( 2πa ). The current I2 can have either of two possible values.

Diagram: http://www.webassign.net/serpop/p22-29.gif

Homework Equations





The Attempt at a Solution



I needed to get this online homework done fast so I had to look up the answers and got I2 = 2*I1 and I2 = 6*I1. These were right but I have no idea how to get them and i struggled with this for about an hour now and still nothing. In my textbook also it only shows how to find the force between them. Its driving me nuts to figure this out and could really use some help on this one.
 
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  • #2
The field at the origin is simply the vector sum of the individual fields due to wire 1 and wire 2.

What's the field at the origin due to wire 1, magnitude and direction?

What's the total field at the origin?
 
  • #3
vela said:
The field at the origin is simply the vector sum of the individual fields due to wire 1 and wire 2.

What's the field at the origin due to wire 1, magnitude and direction?

Wouldn't it just be µI2/(2πa) ?
 
  • #4
Why would it depend on I2 if it's the field due to wire 1? And in what direction does the field point?
 
  • #5
Oh yeah I was trying to find I2, so would it be µI1/2πa and pointing out of the page because of the right hand rule?
 
  • #6
You do want to use the right hand rule, but it doesn't point out of the page. Remember the field lines form circles centered on the wire, so the field will lie in the plane of the page.
 
  • #7
Ohh okay so it would make a Clockwise B- field?
 
  • #8
Yup, so at the origin, the field due to wire 1 points up the page.
 
  • #9
Okay so how have I make that forumla condense down too I2 = 2*I1?
 
  • #10
Apply what I said in post 2. You need to figure this out on your own.
 

FAQ: Current on Parallel Conducting Wires

What is the purpose of studying current on parallel conducting wires?

Studying current on parallel conducting wires is important for understanding the behavior of electricity and how it flows through different paths. This knowledge is crucial in designing electrical circuits and devices.

How is current shared between parallel conducting wires?

In parallel conducting wires, the total current is divided among the wires according to their resistance. Wires with lower resistance will carry more current, while wires with higher resistance will carry less current.

How does the direction of current flow affect parallel conducting wires?

The direction of current flow does not affect the sharing of current between parallel conducting wires. The total current is still divided among the wires according to their resistance, regardless of the direction of flow.

What happens to the total current when more parallel wires are added?

The total current will increase when more parallel wires are added. This is because the total resistance of the circuit decreases, allowing more current to flow through the wires.

What are some practical applications of parallel conducting wires?

Parallel conducting wires are commonly used in household electrical wiring, as well as in electrical circuits for appliances and electronic devices. They are also used in power distribution systems to carry high currents over long distances with minimal loss of energy.

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