- #1
abhaiitg
- 11
- 0
D1=30cm D2=13cm, Q(flow rate)=0.2m3/s, find loss due to sudden contraction and compare it with gradual contraction.
head loss due to suddden contraction is given by (resistance coffiecent* v*v/2*g)
and resistance cooficent is given by (1-(d2/d1)sq)sq) d2 being smaller dia of pipe..
by this we get
resistance coficent k= (1-(13/30)sq)sq=0.659
and head loss as 7.635m
now for gradual loss the resistance cofficent depends on angle it would be
for angle<45 k= 8sin θ/2(1-(d2/d1)sq)sq)
for 45>θ>180 k=(√5sinθ/2)(1-(d2/d1)sq)sq)
the answer is : (v2)^2/2g *(1/Cc-1)^2
cc= 0.63 + 0.37(A2/A1)^3
for gradual loss i don't know the formula :-| , if there is one apart from (v2^2-v1^2)/2g using bernoulli
head loss due to suddden contraction is given by (resistance coffiecent* v*v/2*g)
and resistance cooficent is given by (1-(d2/d1)sq)sq) d2 being smaller dia of pipe..
by this we get
resistance coficent k= (1-(13/30)sq)sq=0.659
and head loss as 7.635m
now for gradual loss the resistance cofficent depends on angle it would be
for angle<45 k= 8sin θ/2(1-(d2/d1)sq)sq)
for 45>θ>180 k=(√5sinθ/2)(1-(d2/d1)sq)sq)
the answer is : (v2)^2/2g *(1/Cc-1)^2
cc= 0.63 + 0.37(A2/A1)^3
for gradual loss i don't know the formula :-| , if there is one apart from (v2^2-v1^2)/2g using bernoulli