Daughter's 6th grade homework question.

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In summary: Smile)In summary, the conversation discusses the 6th grade boy to girl ratio from last year and this year, and the total number of students remaining the same. The problem asks for the number of 6th grade boys last year given that there are 96 girls this year. However, after solving the equations and given information, it appears that there is an error in the problem.
  • #1
teddunner
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I'm at a loss. I can't figure it out. Please help.

Last year's 6th grade boy to girl ratio was 3 to 4. This year's 6th grade boy to girl ratio is 5 to 6. If the total number of students were the same this year as they were last year; what is the number of 6th grade boys last year if there are 96 girls this year?
 
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  • #2
teddunner said:
I'm at a loss. I can't figure it out. Please help.

Last year's 6th grade boy to girl ratio was 3 to 4. This year's 6th grade boy to girl ratio is 5 to 6. If the total number of students were the same this year as they were last year; what is the number of 6th grade boys last year if there are 96 girls this year?

(Wave)

Let $\text{boys_1}$ be the number of boys of last year's 6th grade, $\text{girls_1}$ the number of girls of last year's 6th grade, $\text{boys_2}$ the number of boys of this year's 6th grade and $\text{girls_2}$ the number of girls of this year's 6th grade.

Then the following relations hold:

$$\frac{\text{boys_1}}{\text{girls_1}}=\frac{3}{4}$$

$$\frac{\text{boys_2}}{\text{girls_2}}=\frac{5}{6}$$

$$\text{boys_1}+\text{girls_1}=\text{boys_2}+\text{girls_2}$$

We are looking for the value of $\text{boys_1}$.

We are given that $\text{girls_2}$ is equal to $96$.

So, $\text{boys_2}=\frac{5}{6} \cdot 96=80$.

Also we get that $\text{boys_1}+\text{girls_1}=176$.

Can you continue?
 
  • #3
evinda said:
(Wave)

Let $\text{boys_1}$ be the number of boys of last year's 6th grade, $\text{girls_1}$ the number of girls of last year's 6th grade, $\text{boys_2}$ the number of boys of this year's 6th grade and $\text{girls_2}$ the number of girls of this year's 6th grade.

Then the following relations hold:

$$\frac{\text{boys_1}}{\text{girls_1}}=\frac{3}{4}$$

$$\frac{\text{boys_2}}{\text{girls_2}}=\frac{5}{6}$$

$$\text{boys_1}+\text{girls_1}=\text{boys_2}+\text{girls_2}$$

We are looking for the value of $\text{boys_1}$.

We are given that $\text{girls_2}$ is equal to $96$.

So, $\text{boys_2}=\frac{5}{6} \cdot 96=80$.

Also we get that $\text{boys_1}+\text{girls_1}=176$.

Can you continue?

I can continue, the answer just doesn't make sense. I think it is just an error that slipped through the cracks.
 
  • #4
teddunner said:
I can continue, the answer just doesn't make sense. I think it is just an error that slipped through the cracks.

Yes, I made the calculations and noticed the same. (Nod)
 
  • #5
evinda said:
Yes, I made the calculations and noticed the same. (Nod)

Thank you! I was beginning to think it was just me.
 

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Question 5:

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If your daughter is struggling with her homework question, it is important to offer support and encouragement. You can also reach out to her teacher for additional resources or guidance. It is also helpful to create a study plan and schedule to help your daughter stay organized and on top of her assignments.

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