- #1
mustang1988
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1. Eight lights are connected in parallel to a 119V source by two leads of total resistance 2.5 ohms. If 240mA flows through each bulb what is the resistance of each? What fraction of the total power is wasted in the leads?
2. V=IR, P=I^2(R)
3. V=.24(119)=495.83/8=62ohms
P=(.24)^2(62)=3.57W
These are the answers i got but according to my book they are wrong. Can anyone tell me what I am doing wrong? thanks
2. V=IR, P=I^2(R)
3. V=.24(119)=495.83/8=62ohms
P=(.24)^2(62)=3.57W
These are the answers i got but according to my book they are wrong. Can anyone tell me what I am doing wrong? thanks