- #1
Xyius
- 508
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Not sure if this is the correct place to post this. Technically in my school this math class is above calculus but the problem at hand doesn't have any advanced mathematics. Sorry in advance if it is not correct!
An ordinary deck of 52 cards is dealth, 13 each, at random among A,B,C, and D. What is the probability that (a) A and B together get two aces; (b) A gets all the face cards; (c) A gets five hearts and B gets the remaining eight hearts?
Permutation formula.
[tex]\frac{n!}{(n-k)!}[/tex]
So the probability of getting an ace is 4/52 and the probability of getting another ace is 3/51. Thus the probability of getting two aces is 12/2652? This doesn't seem right. Wouldn't the two events of drawing an ace be NOT independent? Meaning you cannot just multiply their probabilities? I do not understand how to do this problem. Also don't I need to take into account the random distribution of cards? It says the cards are dealt randomly.
Can anyone help me out? :(
Homework Statement
An ordinary deck of 52 cards is dealth, 13 each, at random among A,B,C, and D. What is the probability that (a) A and B together get two aces; (b) A gets all the face cards; (c) A gets five hearts and B gets the remaining eight hearts?
Homework Equations
Permutation formula.
[tex]\frac{n!}{(n-k)!}[/tex]
The Attempt at a Solution
So the probability of getting an ace is 4/52 and the probability of getting another ace is 3/51. Thus the probability of getting two aces is 12/2652? This doesn't seem right. Wouldn't the two events of drawing an ace be NOT independent? Meaning you cannot just multiply their probabilities? I do not understand how to do this problem. Also don't I need to take into account the random distribution of cards? It says the cards are dealt randomly.
Can anyone help me out? :(