- #1
Gerenuk
- 1,034
- 5
Is there some mathematician who knows the "core reason" why exp() is connected with cos()?
I mean I'm confident with "advanced maths for physicists", but maybe some abstract theory gives an answer to this.
I was think of something like:
[tex]|e^{i\phi}|=1[/tex]
therefore it's a unit circle.
But also
[tex]e^{i\phi_1}e^{i\phi_2}=e^{i(\phi_1+\phi_2)}[/tex]
therefore the [itex]\phi[/itex] are have the mathematical structure required for angles. So let's define
[tex]\cos(\phi):=\Re(e^{i\phi})[/tex]
I mean I'm confident with "advanced maths for physicists", but maybe some abstract theory gives an answer to this.
I was think of something like:
[tex]|e^{i\phi}|=1[/tex]
therefore it's a unit circle.
But also
[tex]e^{i\phi_1}e^{i\phi_2}=e^{i(\phi_1+\phi_2)}[/tex]
therefore the [itex]\phi[/itex] are have the mathematical structure required for angles. So let's define
[tex]\cos(\phi):=\Re(e^{i\phi})[/tex]