- #1
delta_moment
- 24
- 0
Given the Law of Reflection:
[tex]\Theta[/tex]'=[tex]\Theta[/tex]
and what I assume in the vector diagram; I have a reason of question.
In english, the law states: The angle of reflection equals the angle of incidence. Now, weigh in diffuse against the specular.
Would, if it could, an area on a std. CD-ROM as it is written, be of a less dense area in one area where there was warping such that it created tiny wells.
Generally, if there where pockets of pitting, could the writing laser be over inundated so as to create a buffer of non-random data. The ever-fire sub-packet. That the computer would interpret as non-error, and it would be written. Say the letter 'N'. To where it is readable, on successive attempts.
Just curious, as all of this is possible, and could explain/define/nay capture the offsetting so many seem to seek...
[tex]\Theta[/tex]'=[tex]\Theta[/tex]
and what I assume in the vector diagram; I have a reason of question.
In english, the law states: The angle of reflection equals the angle of incidence. Now, weigh in diffuse against the specular.
Would, if it could, an area on a std. CD-ROM as it is written, be of a less dense area in one area where there was warping such that it created tiny wells.
Generally, if there where pockets of pitting, could the writing laser be over inundated so as to create a buffer of non-random data. The ever-fire sub-packet. That the computer would interpret as non-error, and it would be written. Say the letter 'N'. To where it is readable, on successive attempts.
Just curious, as all of this is possible, and could explain/define/nay capture the offsetting so many seem to seek...