Definition of the Wilson action on a lattice plaquette?

In summary, the Wilson action for the discrete Yang-Mills model is defined as the sum of the squared differences between the identity matrix and a matrix ##\sigma_p##, which is composed of four square matrices ##\sigma_{e1}, \sigma_{e2}, \sigma_{e3}, \sigma_{e4}## multiplied together. However, the order in which these matrices are multiplied cannot be switched due to the non-commutative nature of matrix multiplication.
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James1238765
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TL;DR Summary
What are the terms to be calculated in the "Wilson action" definition on a Yang-Mills plaquette?
The definition of the Wilson action relating to discrete Yang-Mills model is:

$$ S_{plaq} (\sigma) := \frac{1}{2}\sum_{plaq}\|I_N - \sigma_p\|^2 $$

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(from [here] at 5:55)

It is mentioned that ##\sigma_p## is some kind of a matrix. Could anyone give an explicit example of what a ##\sigma_p## matrix look like, please?

Does the multiplication of sigmas

$$ \sigma_p = \sigma_{e1} \sigma_{e2} \sigma_{e3} \sigma_{e4} $$

mean consecutive matrix multiplication of the four square ##\sigma_e## matrices?
 
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James1238765 said:
TL;DR Summary: What are the terms to be calculated in the "Wilson action" definition on a Yang-Mills plaquette?

Does the multiplication of sigmas

$$ \sigma_p = \sigma_{e1} \sigma_{e2} \sigma_{e3} \sigma_{e4} $$

mean consecutive matrix multiplication of the four square ##\sigma_e## matrices?
In general, matrix multiplications are associative so you can multiply in whatever order works for you. However, matrix multiplcations are not commutative so you can't switch the order around at all.
 
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