Degeneracy pressure of a White Dwarf Star

In summary, the question is asking for the degeneracy pressure of the electron gas in a stable white dwarf star with a mass of 10^30 kg and radius of 8 × 10^8 m. The value of N, the total number of electrons in the star, is required for the calculation. It is suggested that N can be obtained by dividing the mass of the star by the mass of an electron. However, this only works if the white dwarf is composed entirely of electrons. The typical composition of a white dwarf star is mainly carbon-12 and oxygen-16, with one electron for every two nucleons.
  • #1
tanaygupta2000
208
14
Homework Statement
A stable white dwarf star has mass m = 10^30 kg and radius R = 8 ×10^8 m. What is the degeneracy pressure of the electron gas in the star?
Relevant Equations
P = 2πc/3h^3 × P(F)^4 × [1 - {mc/P(F)}^2]
where P(F) = h(3N/8πV)^(1/3)
So far, I am provided with all the required values for calculation, except N.
If N = total number of electrons in star, then using N = mass of star/ mass of an electron should be no problem.
Am I right?
 
Physics news on Phys.org
  • #2
tanaygupta2000 said:
Homework Statement:: A stable white dwarf star has mass m = 10^30 kg and radius R = 8 ×10^8 m. What is the degeneracy pressure of the electron gas in the star?
Relevant Equations:: P = 2πc/3h^3 × P(F)^4 × [1 - {mc/P(F)}^2]
where P(F) = h(3N/8πV)^(1/3)

So far, I am provided with all the required values for calculation, except N.
If N = total number of electrons in star, then using N = mass of star/ mass of an electron should be no problem.
Am I right?
That can't be right.

That would work if the white dwarf star were composed entirely of electrons.
 
  • Like
Likes berkeman
  • #3
SammyS said:
That can't be right.

That would work if the white dwarf star were composed entirely of electrons.
I think N is given by: N = M/(2×Mass of a proton)
 
  • #4
tanaygupta2000 said:
I think N is given by: N = M/(2×Mass of a proton)
That may make sense.

What is the typical composition of a white dwarf star?
 
  • #5
Sir usually WDSs are mainly composed of C-12 & O-16.
But the question here is asking about electron gas.
 
  • #6
tanaygupta2000 said:
Sir usually WDSs are mainly composed of C-12 & O-16.
But the question here is asking about electron gas.
Right. Each of those atoms has 1 electron for every two nucleons (one proton & one neutron). So, yes you were essentially right when you wrote: N = M/(2×Mass of a proton) .
 
  • Like
Likes tanaygupta2000

FAQ: Degeneracy pressure of a White Dwarf Star

What is degeneracy pressure?

Degeneracy pressure is a quantum mechanical phenomenon that occurs when particles are tightly packed together, causing them to resist further compression. This pressure arises due to the Pauli exclusion principle, which states that no two identical fermions can occupy the same quantum state simultaneously.

How does degeneracy pressure support a white dwarf star?

In the late stages of a star's life, when it has exhausted its nuclear fuel, it will collapse due to its own gravity. However, if the star's mass is below a certain limit (known as the Chandrasekhar limit), the degeneracy pressure of its electrons will become strong enough to counteract the force of gravity and prevent further collapse. This creates a stable, compact object known as a white dwarf star.

What factors affect the strength of degeneracy pressure in a white dwarf star?

The strength of degeneracy pressure in a white dwarf star is primarily dependent on the mass of the star. A higher mass will result in a stronger degeneracy pressure, as there are more electrons packed into a smaller volume. Additionally, the density and temperature of the star can also affect the strength of degeneracy pressure.

Can degeneracy pressure ever be overcome in a white dwarf star?

No, degeneracy pressure is a fundamental physical principle that cannot be overcome. However, if a white dwarf star accretes enough mass from a companion star, it can reach the Chandrasekhar limit and collapse into a neutron star or black hole, where degeneracy pressure is replaced by neutron degeneracy pressure or the effects of strong gravity, respectively.

Is degeneracy pressure the only force that supports a white dwarf star?

No, in addition to degeneracy pressure, white dwarf stars are also supported by thermal pressure. This is the pressure generated by the high temperatures in the star's core, which is a result of residual heat from its earlier stages of evolution. However, in the later stages of a white dwarf's life, degeneracy pressure becomes the dominant force supporting the star.

Similar threads

Back
Top