Dependence of Hall coefficient on temperature in semiconductors

In summary, the conversation discusses the temperature dependence of the Hall coefficient and how it can be calculated using the expressions for electron and hole densities. The ionisation energies $E_d$ and $E_a$ and the energy gap of the semiconductor $E_g$ can also be calculated from the final expression of the Hall coefficient. It is also mentioned that the donor and acceptor densities can be found from the Hall coefficient expression.
  • #1
Roger Dalton
4
1
Homework Statement
By measuring the electrical conductivity and the Hall effect as a function of temperature, many characteristic parameters of semiconductors can be determined. Since charge transport in semiconductors takes place through both electrons in the conduction band and holes in the valence band, the two-band model expression for the Hall coefficient must be used.

(a) By measuring the temperature dependence of the Hall coefficient, how can the gap Eg of an n-type semiconductor be determined, as well as the distance Ed from the donor level to the edge of the conducting band? And for a p-type semiconductor, how can the distance Ea from the acceptor level to the valence band edge be determined?

(b) Can the nD density of the donors in an n-type semiconductor or the nA density of the acceptors in a p-type semiconductor be determined by measuring the Hall effect? If so, over what temperature range should the measurement be made?
Relevant Equations
The Hall coefficient for a semiconductor, in terms of the mobilities and the densities of the charge charriers (electrons and holes), is given by:

$$R_H = \frac{1}{e} \frac{p_v\mu_h^2-n_c\mu_e^2}{(p_v\mu_h+n_c\mu_e)^2}$$

Where $\mu_h$ and $\mu_e$ are the mobilities for holes and electrons respectively, and $p_v$ and $n_c$, their respective densities as well.
My first assumption is that the temperature dependence on the mobilities can be neglected, and so we would have:

$$R_H(T)= \frac{1}{e} \frac{p_v(T)\mu_h^2-n_c(T)\mu_e^2}{(p_v(T)\mu_h+n_c(T)\mu_e)^2}$$

The expression for the electron and hole densities could be derived from

$$\frac{n_c(n_c+n_A)}{n_D-n_A-n_c}=n_c^{eff}(T)e^{-E_d/k_BT} (1)$$
$$\frac{p_v(p_v+p_A)}{p_D-p_A-p_v}=p_v^{eff}(T)e^{-E_a/k_BT} (2)$$

Where $E_d$ is the ionisation energy it takes to extract an electron from the donor state to put it into the conduction band, $E_a$ is the ionisation energy it costs to extract a hole to put it in the valence band, and $n_D$, $p_D$, $n_A$, and $p_A$ are the densities of the donor and acceptor densities depending if they are electrons or holes. In this case, we can neglect both $n_A$ and $p_D$.

$$n_c^{eff}(T)=2\left(\frac{m_e^*k_BT}{2\pi\hbar^2}\right)^{3/2}$$
$$p_v^{eff}(T)=2\left(\frac{m_h^*k_BT}{2\pi\hbar^2}\right)^{3/2}$$

Solving (1) and (2) in terms of $n_c(T)$ and $p_v(T)$ and pluging the final expressions into the one for the Hall coeffcient would give us the dependence of Hall coefficient on temperature. Is this approach correct? The thing is that using this approach I do not know what the donor and acceptor densities are.

Besides, how could I calculate the energies $E_a$, $E_d$ and the energy gap of the semiconductor $E_g$ from the final expression of the Hall coeffcient?

Would it also be possible to find the donor and acceptor densities from the Hall coefficient $R_H (T)$ final expression?

Thank you.
 
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  • #2


Your approach to finding the temperature dependence of the Hall coefficient in semiconductors is generally correct. However, there are a few things to keep in mind:

1. Neglecting temperature dependence of mobilities: This assumption is valid only at low temperatures, where the temperature dependence of mobilities is small. At higher temperatures, the mobilities can vary significantly and should be taken into account in the expression for Hall coefficient.

2. Neglecting acceptor and donor densities: In some cases, the acceptor and donor densities can be neglected, but it is not always the case. These densities can have a significant impact on the overall behavior of the semiconductor and should be considered in the calculations.

3. Calculating energies and energy gap: The energies $E_a$ and $E_d$ can be calculated from the expression for Hall coefficient by making certain assumptions about the donor and acceptor densities. The energy gap $E_g$ can also be calculated from the Hall coefficient, but it is a more complex process and may require additional information about the semiconductor material.

4. Finding donor and acceptor densities: It is possible to calculate the donor and acceptor densities from the Hall coefficient, but it is a challenging task. It requires a detailed understanding of the semiconductor material and the assumptions made in the calculations. It is always better to have direct measurements of these densities rather than relying on the Hall coefficient.

In conclusion, your approach is correct, but it is important to consider the limitations and assumptions involved. It is always better to have direct measurements of the relevant parameters rather than relying on indirect calculations.
 

FAQ: Dependence of Hall coefficient on temperature in semiconductors

What is the Hall coefficient and how is it related to semiconductors?

The Hall coefficient (R_H) is a parameter that characterizes the Hall effect in a material, which occurs when a magnetic field is applied perpendicular to the flow of current, resulting in a voltage (Hall voltage) across the material. In semiconductors, the Hall coefficient provides information about the type of charge carriers (electrons or holes), their density, and mobility.

How does temperature affect the Hall coefficient in intrinsic semiconductors?

In intrinsic semiconductors, the Hall coefficient generally decreases with increasing temperature. This is because the intrinsic carrier concentration increases with temperature, leading to a larger number of thermally generated electron-hole pairs. As a result, the net effect of the charge carriers on the Hall coefficient is reduced.

What is the behavior of the Hall coefficient in n-type and p-type semiconductors with temperature changes?

In n-type semiconductors, the Hall coefficient is negative and typically decreases in magnitude with increasing temperature due to the increased carrier concentration. In p-type semiconductors, the Hall coefficient is positive and also tends to decrease with temperature for similar reasons. However, at certain temperature ranges, impurity ionization and changes in carrier mobility can cause more complex behaviors.

Why does the Hall coefficient change with temperature in doped semiconductors?

In doped semiconductors, the Hall coefficient changes with temperature due to the ionization of dopant atoms, which affects the carrier concentration. At low temperatures, not all dopants are ionized, leading to fewer free carriers. As the temperature increases, more dopant atoms ionize, increasing the carrier concentration and thus affecting the Hall coefficient. Additionally, carrier mobility, which is temperature-dependent, also influences the Hall coefficient.

Can the Hall coefficient be used to determine the type and concentration of charge carriers in a semiconductor?

Yes, the Hall coefficient can be used to determine both the type (n-type or p-type) and the concentration of charge carriers in a semiconductor. The sign of the Hall coefficient indicates the type of predominant charge carriers (negative for electrons, positive for holes), and its magnitude is inversely proportional to the carrier concentration. By measuring the Hall voltage and knowing the current, magnetic field, and sample dimensions, one can calculate the carrier concentration and mobility.

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