Derivation of Electric Field with Gauss's Law

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To find the electric field E(r) outside a uniformly charged solid ball of radius rb, Gauss's Law is applied. The enclosed charge is calculated as qencl = ρ(4/3)(π)rb^3, leading to the expression EV = qencl/ε0. The electric field is then derived by equating the electric flux through a spherical surface to the enclosed charge. A division error is noted, as the book's answer is 1/3 of the derived value. The discussion emphasizes the importance of correctly applying Gauss's Law and understanding the relationship between electric field and volume.
k_squared
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I did everything I could to solve the following problem:
A solid ball of radius rb has a uniform charge density ρ.

What is the magnitude of the electric field E(r) at a distance r>rb from the center of the ball?
E(r) =

My third attempt went like this: qencl=[ρ(4/3)(π)rb3]

EV=[ρ(4/3)(π)rb3]/(ε0)
E(4/3)πr3=[ρ(4/3)(π)rb3]/(ε0)

And ah, well, a little simple division and cancelling leads to:
[ρrb3/[ε0r3]

However, the book answer is 1/3 my answer. Could someone please tell me where this constant develops?
 
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Try Gauss's law. Start by writing the equation for Gauss's law.
 
k_squared said:
EV=[ρ(4/3)(π)rb3]/(ε0)
The righthand side is okay. Check the details on the lefthand side of this equation.
 
Why did you multiply the electric field with the volume?
 

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