Derivative of Complex Variables

In summary, the conversation discusses finding the derivative \frac{\partial}{\partial x} of the function |b-ax|^2 and how to approach it. The expert suggests using a Wirtinger derivative and explains the different ways to describe a complex variable. They also mention using the chain rule to find the desired derivative.
  • #1
EngWiPy
1,368
61
Hi,

What is the following derivative:

[tex]\frac{\partial}{\partial x}|b-ax|^2[/tex]?

Now I know that [tex]|b-ax|^2=(b-ax)(b^*-a^*x^*)[/tex], so how to do the differentiation with respect to [tex]x^*[/tex]?

Thanks in advance

PS.: All variables and constants are complex.
 
Mathematics news on Phys.org
  • #3
It is not clear what that derivative means.
A guess would be that it is a Wirtinger derivative in which case we have
[tex]\frac{\partial x^*}{\partial x}=0[/tex]
 
  • #4
Mark44 said:
Is this a homework question?

No it is not.

So lurflurf, are you saying that the derivative will be:

[tex]-a(b-ax)^*[/tex]

I thought it will be like:

[tex]-(b-ax)a^*[/tex]

but I couldn't prove it.
 
  • #5
Again it is not clear what that derivative means, but a good guess would be -a(b-ax)*.
Then we have
d|b-a x|^2=-a(b-a x)* dx+-a*(b-a x) dx*

notice that |b-a x|^2 is definitely not complex differentiable as it depends upon x and x* rather than upon x alone
 
  • #6
lurflurf said:
Again it is not clear what that derivative means, but a good guess would be -a(b-ax)*.
Then we have
d|b-a x|^2=-a(b-a x)* dx+-a*(b-a x) dx*

notice that |b-a x|^2 is definitely not complex differentiable as it depends upon x and x* rather than upon x alone

No, I just need to the derivative [tex]\frac{\partial}{\partial x}[/tex], where the derivative is partial with respect to x. I see some books writing x as a+jb, and then compute the derivatives with respect to a and b. I was just wondering if there is another way to do this.

Thanks
 
  • #7
There are different ways because a complex variable can change in more ways than a real variable. We can work with different coordinates or none. So a function of a complex variable can be described in diferent ways with two variables
|x| and arg(x)
Re(x) and Im(x)
x and x*
and so on

since you are interested in the x partial x and x* are natural, but you could use any set and the chain rule to find the x partial.
[tex]\frac{\partial}{\partial x}=\frac{\partial u}{\partial x}\frac{\partial}{\partial u}+\frac{\partial v}{\partial x}\frac{\partial}{\partial v}[/tex]
However you want to choose u and v
 

FAQ: Derivative of Complex Variables

What are complex variables?

Complex variables are numbers that have both a real and an imaginary component. They are typically represented in the form a + bi, where a is the real part and bi is the imaginary part.

What is a derivative of a complex variable?

The derivative of a complex variable is a mathematical concept that describes the instantaneous rate of change of a complex function. It is similar to the derivative of a real-valued function, but takes into account both the real and imaginary parts of the function.

How is the derivative of a complex variable calculated?

The derivative of a complex variable is calculated using the Cauchy-Riemann equations, which relate the partial derivatives of the real and imaginary parts of a function. These equations can be used to find the derivative at any point in a complex function.

What are some applications of the derivative of complex variables?

The derivative of complex variables has many applications in physics, engineering, and other scientific fields. It is used in the study of fluid dynamics, electromagnetism, and quantum mechanics, among others. It is also used in the development of advanced mathematical models and algorithms.

Are there any special properties of the derivative of complex variables?

Yes, the derivative of a complex variable has several unique properties. For example, it is not always commutative, meaning that the order in which the partial derivatives are taken can affect the result. It also has the property of holomorphicity, which means that if a function is differentiable at a point, it is differentiable at all points in a neighborhood of that point.

Similar threads

Replies
0
Views
954
Replies
5
Views
1K
Replies
2
Views
1K
Replies
2
Views
1K
Replies
16
Views
4K
Replies
19
Views
2K
Replies
5
Views
1K
Back
Top