- #1
Sheen91
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Homework Statement
[PLAIN]http://img697.imageshack.us/img697/6702/bungee.png
Derive the equations of the motion for the jumper. Consider only the vertical motion of the jumper. (g = 9.81 m/s^2)
Homework Equations
Straing = (Stated Above)
Strain Rate = v / lo = v/25
F = -kx (Hooke's Law)
The Attempt at a Solution
We aren't really given formula, but required to go out and seek and find them and find a way to solve the Question.
I know the Equation needs to be a piecewise equation.
First part will be for the free fall the bungee jumper will feel before hitting the 25 meter mark where the bungees spring force will be felt by the bungee jumper.
I think we can just use the simple equation:
d = u*t + 1/2 *a*t^2
Since d = l, u = 0
l = 1/2 * a * t^2 = 9.81/2 * t^2
So for 0 < l < 25 , l = 9.81/2 * t^2
For the second part of the equation I am a little stumped.
We do not need to take air resistance into account.
Thanks in advance, and any and all help will be greatly appreciated.
Cheers,
Sheen
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