Deriving Common Moments of Inertia: Sphere I=\frac{2}{5}mr^{2}

In summary, the conversation was about how to find the common moments of inertia for a uniform sphere. The group discussed the general form of the moment of inertia, which involves an integral of the mass distribution and moments of the mass. They also shared a link that provides an example of the integration used to determine the moment of inertia. The conversation also touched on defining the center of mass and the steps involved in finding the moment of inertia for a sphere.
  • #1
amcavoy
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Could someone direct me to a site that explains how the common moments of inertia were arrived at? My physics professor put up on the board today that for a uniform sphere:

[tex]I=\frac{2}{5}mr^{2}.[/tex]

He said it was just the anti-derivative of something, but he didn't want to go into it because there is a table in our book with all of the common moments of inertia.

Does anyone know? Maybe someone could show me how the above moment (for the sphere) was derived and I could try it on something else? Thanks, I'd appreciate it.
 
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  • #2
The general form of the moment of inertia involves an integral of the mass distribution and moments of the mass.

http://hyperphysics.phy-astr.gsu.edu/hbase/mi.html#mi

The fourth and fifth plates provide an example of the integration ('anti-derivative') used to determine the moment of inertia.

Think about how a center of mass is defined.
 
  • #3
You need to integrate [tex]r^2 \sin^2 \theta[/tex] over the volume of the sphere. Note that this represents the square of the perpendicular distance of a point in the sphere from the axis of rotation. Also, note that [tex]dV = r^2 dr d\phi \sin \theta d\theta[/tex].
 

FAQ: Deriving Common Moments of Inertia: Sphere I=\frac{2}{5}mr^{2}

What is the equation for deriving the moment of inertia of a sphere?

The equation for deriving the moment of inertia of a sphere is I = (2/5)mr^2, where I is the moment of inertia, m is the mass of the sphere, and r is the radius of the sphere.

How is the moment of inertia of a sphere related to its shape?

The moment of inertia of a sphere is directly proportional to its shape, specifically its radius. This means that the larger the radius of the sphere, the larger its moment of inertia will be.

Can the moment of inertia of a sphere be negative?

No, the moment of inertia of a sphere cannot be negative. It is always a positive value that represents the resistance of an object to changes in its rotational motion.

How is the moment of inertia of a sphere different from other shapes?

The moment of inertia of a sphere is unique because it is the same regardless of its orientation. This means that no matter how the sphere is rotated, its moment of inertia will remain constant.

What is the significance of the (2/5) term in the moment of inertia equation for a sphere?

The (2/5) term in the moment of inertia equation for a sphere is a numerical constant that represents the distribution of mass within the sphere. It is a result of the uniform density of a sphere and is used to calculate its moment of inertia accurately.

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