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Homework Statement
Show that the exit intensity as a function of Io (intensity out of light source) and θ12 (angle of second polarizer compared to the first polarizer) is
I = (Io/8) sin(2(θ12)))^2
Homework Equations
Malus' Law
I = Io (cosθ)^2
The Attempt at a Solution
I1 = Io/2
I2 = I1 (cos(θ12))^2
= (Io/2) (cos(θ12))^2
I = I2 (cos(θ23))^2
= (Io/2)(cos(θ12))^2 (cos(θ23))^2
I understand that the difference between θ1 and θ13 is 90°, but don't know how to apply this to derive the equation listed above.