- #1
Elekko
- 17
- 0
On the book "Introduction to Solid State Physics" by Kittel, on page 98 he derived the roots for optical and acoustical branches for the equation:
[tex]M_1 M_2 \omega^4-2C(M_1+M_2)\omega^2+2C^2(1-cos(Ka))=0[/tex]
where the roots are:
[tex]\omega^2=2C(\frac{1}{M_1}+\frac{1}{M_2})[/tex] and
[tex]\omega^2=\frac{\frac{1}{2}C}{M_1+M_2}K^2 a^2[/tex]
I'm wondering how he actually found these roots since he skipped the details? He only mentions the trigonometric identity can be set to zero... how are the roots found?
[tex]M_1 M_2 \omega^4-2C(M_1+M_2)\omega^2+2C^2(1-cos(Ka))=0[/tex]
where the roots are:
[tex]\omega^2=2C(\frac{1}{M_1}+\frac{1}{M_2})[/tex] and
[tex]\omega^2=\frac{\frac{1}{2}C}{M_1+M_2}K^2 a^2[/tex]
I'm wondering how he actually found these roots since he skipped the details? He only mentions the trigonometric identity can be set to zero... how are the roots found?