- #1
Oriako
- 107
- 1
I'm attempting to derive speed in terms of potential difference (voltage), can anyone let me know if there are any errors?
[PLAIN]http://www.texify.com/img/%5CLARGE%5C%21E_k%3D%5Cfrac%7B1%7D%7B2%7D%5Ctext%7Bmv%7D%5E2.gif
[PLAIN]http://www.texify.com/img/%5CLARGE%5C%21v%3D%5Csqrt%7B%5Cfrac%7B2E_p%7D%7Bm%7D%7D.gif, since [PLAIN]http://www.texify.com/img/%5CLARGE%5C%21E_k%3DE_p.gif
[PLAIN]http://www.texify.com/img/%5CLARGE%5C%21v%3D%5Csqrt%7B%5Cfrac%7B2%28%5Ctext%7Bma%24%5CDelta%20%24d%7D%29%7D%7Bm%7D%7D.gif, since [PLAIN]http://www.texify.com/img/%5CLARGE%5C%21E_p%3D%5Ctext%7Bmg%24%5CDelta%20%24h%7D%20.gif may be generalized to [PLAIN]http://www.texify.com/img/%5CLARGE%5C%21E_p%3D%5Ctext%7Bma%24%5CDelta%20%24d%7D.gif for electric energy.
[PLAIN]http://www.texify.com/img/%5CLARGE%5C%21v%3D%5Csqrt%7B%5Cfrac%7B2%5Cleft%28F_%7B%5Ctext%7Bnet%7D%7D%5Ctext%7B%24%5CDelta%20%24d%7D%5Cright%29%7D%7Bm%7D%7D.gif, since [PLAIN]http://www.texify.com/img/%5CLARGE%5C%21F_%7B%5Ctext%7Bnet%7D%7D%3D%5Ctext%7Bma%7D.gif
[PLAIN]http://www.texify.com/img/%5CLARGE%5C%21v%3D%5Csqrt%7B%5Cfrac%7B2W%7D%7Bm%7D%7D.gif, since [PLAIN]http://www.texify.com/img/%5CLARGE%5C%21W%3DF_%7B%5Ctext%7Bnet%7D%7D%5Ctext%7B%24%5CDelta%20%24d%7D.gif
[PLAIN]http://www.texify.com/img/%5CLARGE%5C%21v%3D%5Csqrt%7B%5Cfrac%7B2%5Ctext%7B%24%5CDelta%20%24E%7D%7D%7Bm%7D%7D.gif, since [PLAIN]http://www.texify.com/img/%5CLARGE%5C%21%5Ctext%7B%24%5CDelta%20%24E%7D%20%3D%20W.gif
[PLAIN]http://www.texify.com/img/%5CLARGE%5C%21v%3D%5Csqrt%7B%5Cfrac%7B2%28%5Ctext%7B%24%5CDelta%20%24Vq%7D%29%7D%7Bm%7D%7D.gif, since [PLAIN]http://www.texify.com/img/%5CLARGE%5C%21%5Ctext%7B%24%5CDelta%20%24Vq%7D%3D%5Ctext%7B%24%5CDelta%20%24E%7D.gif
Therefore, speed is equal to the square root of double the product of charge and potential difference divided by mass.
Thanks!
[PLAIN]http://www.texify.com/img/%5CLARGE%5C%21E_k%3D%5Cfrac%7B1%7D%7B2%7D%5Ctext%7Bmv%7D%5E2.gif
[PLAIN]http://www.texify.com/img/%5CLARGE%5C%21v%3D%5Csqrt%7B%5Cfrac%7B2E_p%7D%7Bm%7D%7D.gif, since [PLAIN]http://www.texify.com/img/%5CLARGE%5C%21E_k%3DE_p.gif
[PLAIN]http://www.texify.com/img/%5CLARGE%5C%21v%3D%5Csqrt%7B%5Cfrac%7B2%28%5Ctext%7Bma%24%5CDelta%20%24d%7D%29%7D%7Bm%7D%7D.gif, since [PLAIN]http://www.texify.com/img/%5CLARGE%5C%21E_p%3D%5Ctext%7Bmg%24%5CDelta%20%24h%7D%20.gif may be generalized to [PLAIN]http://www.texify.com/img/%5CLARGE%5C%21E_p%3D%5Ctext%7Bma%24%5CDelta%20%24d%7D.gif for electric energy.
[PLAIN]http://www.texify.com/img/%5CLARGE%5C%21v%3D%5Csqrt%7B%5Cfrac%7B2%5Cleft%28F_%7B%5Ctext%7Bnet%7D%7D%5Ctext%7B%24%5CDelta%20%24d%7D%5Cright%29%7D%7Bm%7D%7D.gif, since [PLAIN]http://www.texify.com/img/%5CLARGE%5C%21F_%7B%5Ctext%7Bnet%7D%7D%3D%5Ctext%7Bma%7D.gif
[PLAIN]http://www.texify.com/img/%5CLARGE%5C%21v%3D%5Csqrt%7B%5Cfrac%7B2W%7D%7Bm%7D%7D.gif, since [PLAIN]http://www.texify.com/img/%5CLARGE%5C%21W%3DF_%7B%5Ctext%7Bnet%7D%7D%5Ctext%7B%24%5CDelta%20%24d%7D.gif
[PLAIN]http://www.texify.com/img/%5CLARGE%5C%21v%3D%5Csqrt%7B%5Cfrac%7B2%5Ctext%7B%24%5CDelta%20%24E%7D%7D%7Bm%7D%7D.gif, since [PLAIN]http://www.texify.com/img/%5CLARGE%5C%21%5Ctext%7B%24%5CDelta%20%24E%7D%20%3D%20W.gif
[PLAIN]http://www.texify.com/img/%5CLARGE%5C%21v%3D%5Csqrt%7B%5Cfrac%7B2%28%5Ctext%7B%24%5CDelta%20%24Vq%7D%29%7D%7Bm%7D%7D.gif, since [PLAIN]http://www.texify.com/img/%5CLARGE%5C%21%5Ctext%7B%24%5CDelta%20%24Vq%7D%3D%5Ctext%7B%24%5CDelta%20%24E%7D.gif
Therefore, speed is equal to the square root of double the product of charge and potential difference divided by mass.
Thanks!
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