Deriving taylor series for v/c and gamma

In summary, the velocity of a proton relative to our galaxy is almost one, which means that the value of gamma is very large. Using a Taylor series, we can express v/c as a function of 1/gamma squared. When v is almost one, this function can be approximated as 1-(1/2)(1/gamma^2), which shows the relationship between velocity and gamma.
  • #1
warfreak131
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Homework Statement



The velocity of a proton relative to
our galaxy is vp/c = 1-(0.5*10^20), i.e. almost one. Such protons are actually observed.

When velocity it very nearly one [tex]\gamma[/tex] is very large. 1/[tex]\gamma[/tex]
is very small. Use Taylor series to show that for v almost one we have

v/c[tex]\approx[/tex]1-(1/2)(1/[tex]\gamma^{2}[/tex])...

Homework Equations





The Attempt at a Solution



I haven't done Taylor series for about a year now, and I don't quite remember how to do it. The teacher gives us some basic info on the mathematics needed to do the homework, but I can't seem to figure out a relationship. I've also looked for explanations of taylor series relevant to my question, but I haven't found anything
 
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  • #2
First, express v/c as a function of 1/γ2. Then expand that function as a Taylor series about 1/γ2=0.

f(x) = f(0) + f'(0)x + f''(0)x2/2! + f'''(0)x3/3! + ...
 
  • #3
I imagine that you could also just do a taylor expansion on gamma and it would give you similar results, though I have to admit I haven't looked into it. This is just what's normally done.
 

FAQ: Deriving taylor series for v/c and gamma

What is the purpose of deriving Taylor series for v/c and gamma?

The purpose of deriving Taylor series for v/c and gamma is to better understand the relationship between velocity, the speed of light, and the Lorentz factor (gamma) in special relativity. This series allows us to approximate these values for small changes in velocity.

What is the formula for the Taylor series for v/c?

The formula for the Taylor series for v/c is v/c = 1 + 1/2 (v/c)^2 + 1/8 (v/c)^4 + ...

How is the Taylor series for v/c derived?

The Taylor series for v/c is derived by taking the Maclaurin series expansion of the function 1/sqrt(1-(v/c)^2). This involves taking derivatives of the function at a specific value, in this case v/c = 0, and plugging them into the Maclaurin series formula.

What is the significance of the Taylor series for gamma?

The Taylor series for gamma allows us to approximate the Lorentz factor for small changes in velocity. This is important in understanding the effects of special relativity at high speeds and in making calculations in fields such as physics and engineering.

Can the Taylor series for v/c and gamma be used for any velocity?

The Taylor series for v/c and gamma is only accurate for small changes in velocity, typically up to around 0.5c. For larger velocities, the series diverges and becomes increasingly inaccurate. Therefore, it is only applicable to low velocity situations, such as in everyday life. For high velocity situations, other mathematical methods must be used to accurately calculate v/c and gamma.

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