Deriving the Lens Maker formula of a plano-convex lens using Fermat's Principle

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The discussion focuses on deriving the Lens Maker's formula for a plano-convex lens using Fermat's Principle. The main challenge is determining the correct variable to differentiate when analyzing the time taken by different rays of light. It is suggested to differentiate with respect to the height parameter, h, as this represents different rays originating from a point source placed far from the lens. The symmetry of the lens ensures that rays hitting at the same height will take the same time to travel through the lens. Understanding this symmetry is crucial for correctly applying Fermat's Principle to derive the formula.
Clara Chung
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Homework Statement


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Homework Equations

The Attempt at a Solution


I only need help on part c. I tried to add up t1 and t2 and differentiate it. However what variables should I differentiate with respect to? If I differentiate with respect to f I got f=root(2) * h, if i differentiate with respect to R i get R tends to infinity. What should I do?
 

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You want different rays all to take the same time. What parameter selects different rays?
 
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TSny said:
You want different rays all to take the same time. What parameter selects different rays?
I should differentiate with respect to h. However, why do different rays all take the same time? Shouldn't there be different quickest light path for different h?
 
Clara Chung said:
I should differentiate with respect to h. However, why do different rays all take the same time? Shouldn't there be different quickest light path for different h?
Feynman has a nice discussion here
http://www.feynmanlectures.caltech.edu/I_26.html

You can skip to the paragraph just before Fig 26-9 and read this as well as the next paragraph. (But if you do skip, you will miss Feynman's derivation of Snell's law (eq. 26.4) from Fermat's principle that doesn't use calculus!)

To relate this to your problem, you will want to consider the point ##P## as placed "infinitely far" to the left of the lens. Then ##P'## will be at a focal point of the lens. All the rays from ##P## that pass through the lens will be essentially horizontal. So, changing ##h## will correspond to different rays from ##P##. There will also be different rays that hit the lens in a circle at the same ##h## corresponding to rotating the figure about the horizontal axis of the lens. But, by symmetry, these will clearly take the same time from ##P## to ##P'##.
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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