- #1
electronic engineer
- 145
- 3
We were asked to design digital voltage and current meter with 3 ranges
(20 100 200) v for voltages and two ranges
(2, 20)A for amperes
Note: supply voltage is 5V
maximum value for resistors of ampere meter must not exceeded 0.5 ohm
V1=Vin. (R2+R3+R4)/(R1+R2+R3+R4)
V2=Vin.(R3+R4)/(R1+R2+R3+R4)
V3=Vin.(R4)/(R1+R2+R3+R4)
Where V1=V2=V3=V4=1 V
Vin changes respectively with V1,V2,V3 as 20,100,200
So we used those equations mentioned above when we considered R1+R2+R3+R4=6000 Kohm but we get these values:
R4=R3=30Kohm
R2= -30
Note: we have no problem with current meter,that's why I haven't referred to it at the attachment
Need help!
Thanks in advance!
(20 100 200) v for voltages and two ranges
(2, 20)A for amperes
Note: supply voltage is 5V
maximum value for resistors of ampere meter must not exceeded 0.5 ohm
V1=Vin. (R2+R3+R4)/(R1+R2+R3+R4)
V2=Vin.(R3+R4)/(R1+R2+R3+R4)
V3=Vin.(R4)/(R1+R2+R3+R4)
Where V1=V2=V3=V4=1 V
Vin changes respectively with V1,V2,V3 as 20,100,200
So we used those equations mentioned above when we considered R1+R2+R3+R4=6000 Kohm but we get these values:
R4=R3=30Kohm
R2= -30
Note: we have no problem with current meter,that's why I haven't referred to it at the attachment
Need help!
Thanks in advance!