- #1
nathanfan
- 1
- 0
Dear everyone, this is my first post here. Nice to meet you all.
Now I have my project to design a catilever which can be used as accelerometer. The current stage is to have the vibration motion of the cantilever formulated using FEM, and then the design parameters can be substituted into the formula and check whether the natural frequency of the cantilever is within the expected region.
So my knowledge is only for the consistent mass FEM equation of the bar with uniform thickness and properties. I don't know how to formulate a cantilever which has a mass at its end, the mass would be dominating.
So what can I do? divide the cantilever into two elements, one without the mass while the other with the mass? If so, if I assume the cross-sectional area and density for both area to be identical ( in fact the mass would be a bit large and made by cast iron, while the beam would be made by aluminium alloy), would the error be so significant?
My stage now is a estimation of the dimension using the formula generated.
So thanks very much for the patience and kind participation.
Now I have my project to design a catilever which can be used as accelerometer. The current stage is to have the vibration motion of the cantilever formulated using FEM, and then the design parameters can be substituted into the formula and check whether the natural frequency of the cantilever is within the expected region.
So my knowledge is only for the consistent mass FEM equation of the bar with uniform thickness and properties. I don't know how to formulate a cantilever which has a mass at its end, the mass would be dominating.
So what can I do? divide the cantilever into two elements, one without the mass while the other with the mass? If so, if I assume the cross-sectional area and density for both area to be identical ( in fact the mass would be a bit large and made by cast iron, while the beam would be made by aluminium alloy), would the error be so significant?
My stage now is a estimation of the dimension using the formula generated.
So thanks very much for the patience and kind participation.