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dpa said:Hi all,
This is a beginning step in proving aXb=|a||b|sin(theta)
thank you
The determinant of a vector of AXB for 3-D is a mathematical operation that calculates the signed volume of a parallelepiped formed by three vectors - A, B, and the cross product of A and B (AXB). It is also known as the scalar triple product.
The determinant of a vector of AXB for 3-D can be calculated using the formula: det(AXB) = (A x B) · C, where C is the third vector perpendicular to both A and B. Another method is to use the components of the three vectors and apply the determinant formula for a 3x3 matrix.
The determinant of a vector of AXB for 3-D has various applications in mathematics and physics. It is used to calculate the volume of a parallelepiped, determine whether three vectors are linearly independent, and find the area of a triangle in 3-D space. It is also used in the study of cross products and their properties.
The determinant of a vector of AXB for 3-D is related to the orientation of vectors in the sense that it determines whether the vectors are pointing in the same direction (positive determinant), opposite direction (negative determinant), or are coplanar (zero determinant). It also indicates the direction of the cross product vector (right-hand rule).
Yes, the determinant of a vector of AXB for 3-D can be negative. This occurs when the three vectors are arranged in a counterclockwise orientation. In this case, the volume of the parallelepiped formed is considered to be negative. However, the absolute value of the determinant remains the same regardless of the orientation of the vectors.