Determinant problem, matrices wee

In summary, The problem at hand is finding determinants of a 4x4 matrix with rows v_1, v_2, v_3, and v_4, with a given determinant of -6. The first part, part a, requires finding the determinant of a matrix with a multiple of 5 in the first row and the same rows as the original matrix. The second part, part b, involves finding the determinant of a matrix with the rows in reverse order, which results in a change in sign. The third part, part c, asks for the determinant of a matrix with the fourth row added to 7 times the second row. The solution to part c involves using the linearity of the determinant, and
  • #1
mr_coffee
1,629
1
Determinant problem, matrices! wee!

Hello everyone...
I got part a, and b, and I'm stuck on c...
Suppose that a 4 x 4 matrix A with rows v_1, v_2, v_3, and v_4 has determinant det A = -6. Find the following determinants determinants:

det[v_1 v_2 v_3 v_4 + 7*v_2]^T = ?
I made it Transposed so its more readable...really it is just
determinant of
v_1
v_2
v_3
v_4 + 7*v_2

I tried 7*-6 = -42 which was wrong, because if u multiply a column by a constant, it just mutlipies the matrix by that constant, but i don't know what happens if u multip[ly a constant to a a row, and then add it to another row..
Any ideas?
If ur confused on what I'm talking about, here is an answer to part a:
5*v_1
v_2
v_3
v_4

det of that matrix is: 5*-6 = -30;

and part b:
v_4
v_3
v_2
v_1
det of that matrix is 6, because if u swap rows, it will change the sign of the detemrinant.
 
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  • #2
You can use the (multi)linearity of the determinant:

[tex]\left| {\begin{array}{*{20}c}
{a_{11} } & {a_{12} } \\
{\alpha a_{21} + \beta a_{21} ^\prime } & {\alpha a_{22} + \beta a_{22} ^\prime } \\
\end{array}} \right| = \alpha \left| {\begin{array}{*{20}c}
{a_{11} } & {a_{12} } \\
{a_{21} } & {a_{22} } \\
\end{array}} \right| + \beta \left| {\begin{array}{*{20}c}
{a_{11} } & {a_{12} } \\
{a_{21} ^\prime } & {a_{22} ^\prime } \\
\end{array}} \right|[/tex]

By the way, for b: mind that every single row-swap changes the sign, so an even number of swaps...
 
  • #3
thank u TD! but when u said for part b...if its a even number of swaps, wouldn't the determinatant not be changedf at all? it would go from -6 to 6 to -6 to 6, oh wait yah it would thanks!
 
  • #4
mr_coffee said:
thank u TD! but when u said for part b...if its a even number of swaps, wouldn't the determinatant not be changedf at all? it would go from -6 to 6 to -6 to 6, oh wait yah it would thanks!
Indeed :wink:
 

FAQ: Determinant problem, matrices wee

What is a determinant in matrices?

A determinant is a numerical value that can be calculated from a square matrix. It represents certain properties of the matrix, such as its size, shape, and orientation. It is often used in linear algebra and plays a crucial role in solving systems of linear equations.

How do you find the determinant of a matrix?

The determinant of a matrix can be found by using various methods, such as cofactor expansion, row reduction, or using the rule of Sarrus for 3x3 matrices. The specific method used depends on the size and complexity of the matrix.

What does the determinant tell us about a matrix?

The determinant can tell us important information about a matrix, such as whether the matrix is invertible or singular, the volume or area of a geometric shape represented by the matrix, and the linear dependence or independence of the matrix's columns or rows.

Can a matrix have a determinant of 0?

Yes, a matrix can have a determinant of 0. This means that the matrix is singular and does not have an inverse. It also indicates that the matrix's columns or rows are linearly dependent, and the matrix cannot be used to solve systems of linear equations.

How is the determinant useful in solving real-world problems?

The determinant is a powerful tool in solving real-world problems, especially in fields such as physics, engineering, and economics. It can be used to determine the stability of a system, calculate areas and volumes, and identify optimal solutions in optimization problems.

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