Determine Dimensions of Physical Quantities: F, p

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In summary, the dimensions of the physical quantities force and pressure are:a) Force, F: F = M(LT^-2)b) Pressure, p: p = ML^-1T^-2
  • #1
you_of_eh
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From the following defining equations, determine the dimensions of the names physical quantities. Use L to represent the dimension length (distance), T to represent time and M to represent mass.

a) force, F: F=ma, (where m is mass and a is acceleration)
b) pressure, p: p=F/A, (where F is a force (see previous question) and A is an area)

-I don't need the answer it's just that I can't even attempt to solve the question as I have no idea what the question is asking for.

a) F=M*d(L/T)/dT ?
b) p=M*d(L/T)/dT/L^2 ?

..that is all that I could come up with.

Thank you for your time.
 
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  • #2
you_of_eh said:
From the following defining equations, determine the dimensions of the names physical quantities. Use L to represent the dimension length (distance), T to represent time and M to represent mass.

a) force, F: F=ma, (where m is mass and a is acceleration)
b) pressure, p: p=F/A, (where F is a force (see previous question) and A is an area)

-I don't need the answer it's just that I can't even attempt to solve the question as I have no idea what the question is asking for.

a) F=M*d(L/T)/dT ?
b) p=M*d(L/T)/dT/L^2 ?

..that is all that I could come up with.

Thank you for your time.

Welcome to the PF. You are close... For a), just clean up what you have, and leave out the d symbols. The units of a change in length are still length. Does that help?
 
  • #3
OK yea I get it..

a) F = M(L^3)(T^2)
b) p = ML/T^2
 
  • #4
you_of_eh said:
OK yea I get it..

a) F = M(L^3)(T^2)
b) p = ML/T^2

Much closer. But you messed up a division in a) (I didn't check b).

Hint -- The unit of force is a Newton. Look up what the sub-units are that make up a N.
 
  • #5
Well I checked it a couple times..seems correct to me.
 
  • #6
Try plugging in actual units. M = kg, L = m, T = s

For a) you're saying F = M(L^3)(T^2)

which means, N(Newton) = kg * m3 * s2, and that is close, but not right.

Edit: Also, b) is wrong. Again, p = ML/T^2 is close, but not right.

You're saying, p = kg * m / s2
 
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FAQ: Determine Dimensions of Physical Quantities: F, p

How do you determine the dimensions of force (F)?

The dimensions of force, or F, can be determined using the equation F = m * a, where m is mass and a is acceleration. Therefore, the dimensions of force are mass multiplied by acceleration, or [M] * [L/T^2].

What are the units of force?

The SI unit for force is the Newton (N). Other common units of force include pound-force (lbf) and kilogram-force (kgf).

How do you calculate the dimensions of momentum (p)?

The dimensions of momentum, or p, can be calculated using the equation p = m * v, where m is mass and v is velocity. Therefore, the dimensions of momentum are mass multiplied by velocity, or [M] * [L/T].

What are the units of momentum?

The SI unit for momentum is kilogram-meter per second (kg*m/s). Other common units include gram-centimeter per second (g*cm/s) and pound-foot per second (lbf*ft/s).

How are force and momentum related?

Force and momentum are closely related, as force is the rate of change of momentum. Therefore, when a force acts on an object, it causes a change in the object's momentum. This relationship is described by the equation F = dp/dt, where F is force, p is momentum, and t is time.

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