- #1
jr5
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- TL;DR Summary
- A hydraulic actuator force, F is 3000m from the right is lifting the platform upwards. The load 12000kg is UDL. How do I calculate for F?
In summary, the conversation discusses the acceleration of a load and its dependence on cylinder geometry. It is also mentioned that the load is calculated at 12,000 kg and questions are raised about the safety of the support. The conversation ends with the thread being closed due to the discussion being deemed dangerous.
- #2
erobz
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Is it accelerating the load? ##F## will also be a function of the cylinder geometry.
- #3
jr5
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No it's not accelerating the load. The cylinder geometry will be depending on the calculated force.
- #4
Baluncore
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Moment: 12,000 kg at 3.000 m = 36,000 kg⋅m .
If one lift cylinder is located at 1.906 m from the fulcrum,
the load will be; 36,000 / 1.906 = 18,888. kg .
18,888 kg * 9.8 = 185,100 newton.
Have you included the mass of the tilting platform?
If one lift cylinder is located at 1.906 m from the fulcrum,
the load will be; 36,000 / 1.906 = 18,888. kg .
18,888 kg * 9.8 = 185,100 newton.
Have you included the mass of the tilting platform?
- #5
berkeman
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The load is 12,000 kg, and you are asking for advice on an Internet forum? Can you provide a link to your buisiness insurance company please?jr5 said:
- #6
jr5
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It's not for company, it's a mockup.berkeman said:
- #7
berkeman
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I don't understand. Is the load really 12,000 kg, or is that mocked up too? If it's real, what happens if/when the support fails?jr5 said:
- #8
DeBangis21
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Jeopardy.berkeman said:
- #9
berkeman
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You are not helping your case to keep this thread open; thread is now closed per the "no dangerous discussions" clause in the PF Rules (see INFO at the top of the page).DeBangis21 said:
FAQ: Determine Force for inclining platform
What is the formula to determine the force required to incline a platform?
The formula to determine the force required to incline a platform is \( F = m \cdot g \cdot \sin(\theta) \), where \( F \) is the force, \( m \) is the mass of the object on the platform, \( g \) is the acceleration due to gravity, and \( \theta \) is the angle of inclination.
How does the angle of inclination affect the required force?
The angle of inclination (\( \theta \)) affects the required force in that as the angle increases, the sine of the angle (\( \sin(\theta) \)) increases, which in turn increases the required force. Essentially, a steeper angle requires more force to maintain the incline.
What role does friction play in determining the force for an inclining platform?
Friction plays a significant role in determining the force required. The actual force needed is the sum of the force to overcome gravity and the force to overcome friction. The frictional force can be calculated using \( F_f = \mu \cdot N \), where \( \mu \) is the coefficient of friction and \( N \) is the normal force, which is \( m \cdot g \cdot \cos(\theta) \).
How do you account for different coefficients of friction in the calculation?
To account for different coefficients of friction, you need to include the frictional force in your total force calculation. The total force \( F_{total} \) becomes \( F_{total} = m \cdot g \cdot \sin(\theta) + \mu \cdot m \cdot g \cdot \cos(\theta) \). This incorporates both the gravitational component along the incline and the frictional resistance.
Can the force required to incline a platform be reduced? If so, how?
Yes, the force required to incline a platform can be reduced by either decreasing the mass of the object, reducing the angle of inclination, or minimizing the coefficient of friction between the platform and the object. Using lubrication or smoother surfaces can help reduce the coefficient of friction.