Determine if "n squared - n + 41 is prime" is True or False

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In summary, the statement "n squared - n + 41 is prime for all natural numbers n" is false. This is because when n equals 41, the result is 41 squared, which is not prime. This was confirmed by checking it on the computer and verifying that it is only true for n < 41.
  • #1
Joystar77
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Let S (n) be the sentence

n squared - n + 41 is prime for all natural numbers n.

Determine if S (n) is a true or false sentence.

Is this a true sentence? If not, can somebody please explain this to me?
 
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  • #2
We have $41^2-41+41=41^2$, which clearly is not prime. So, $S(n)$ is a false sentence.
 
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  • #3
Thanks for explaining this Fernando!I really and truly appreciate it.
 
  • #4
I checked on the computer that $S(n)$ is true for all $n<41$.
 
  • #5
Thank you Evgeny. Makarov for double checking this.



Joystar1977
 
  • #6
Evgeny.Makarov is this problem done correctly?

Let S (n) be the sentence

n squared - n + 41 is prime for all natural numbers n.

S (41) = 41 squared - 41 + 41 = 41 squared, which clearly is not prime.
 
  • #7
Joystar1977 said:
Let S (n) be the sentence

n squared - n + 41 is prime for all natural numbers n.

S (41) = 41 squared - 41 + 41 = 41 squared, which clearly is not prime.
First, there may be a typo in the problem statement. It should say either "Let $S(n)$ be '$n^2-n+41$ is prime'" or "Let $S$ be '$n^2-n+41$ is prime for all $n$'". Recall that a proposition is something that can be either true or false. In the first case the truth value of $S(n)$ depends on $n$, and for each concrete $n$, $S(n)$ is a proposition. In the second case the truth value of $S$ does not depend on anything, and $S$ itself is a proposition.

Let's assume we have the first case. Then $S(41)$ is a proposition, i.e., true or false. It is important that, in particular, it cannot equal a number and you can't write that $S(41)=41$. Instead, you should write, "When $n=41$, $n^2-n+41=41^2$, which is not prime; therefore, $S(41)$ is false, which in turn means that "For all $n$, $S(n)$" is also false.

Hint: It is customary to write n^2 for $n^2$ in plain text.
 
  • #8
Thanks for rechecking on this Evgeny.Makarov!
 

FAQ: Determine if "n squared - n + 41 is prime" is True or False

What is "n squared - n + 41"?

"n squared - n + 41" is a mathematical expression that represents a polynomial function with a variable, n, raised to the power of 2, subtracted by n, and added by 41.

How do you determine if "n squared - n + 41" is prime?

To determine if "n squared - n + 41" is prime, we need to substitute different values for n and check if the resulting expression is divisible only by 1 and itself. If this condition is met for all values of n, then the expression is prime. However, if we find even one value of n for which the expression is divisible by a number other than 1 and itself, then the expression is not prime.

What is the significance of "41" in the expression "n squared - n + 41"?

The number 41 is significant because it is a prime number. When this number is added to the expression "n squared - n", it creates a pattern where the resulting expression is prime for the first 41 values of n. This is known as the Euler's prime-generating polynomial.

Can you provide an example of a value of n for which "n squared - n + 41" is not prime?

Yes, for example, when n = 42, the expression "n squared - n + 41" becomes 42 squared - 42 + 41 = 1763, which is divisible by 41 and 43. Hence, the expression is not prime for this value of n.

Is there a general rule to determine if "n squared - n + 41" is always prime?

No, there is no general rule to determine if "n squared - n + 41" is always prime. This expression is an example of a polynomial function that produces prime numbers for some values of n and composite numbers for others. Each polynomial function has its own unique pattern, and there is no one formula that can determine the primality of all polynomial expressions.

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