- #1
Vladi
Homework Statement
A beam of electrons passes undeflected through two mutually perpendicular electric and magnetic fields. If the electric field is cut off and the same magnetic field maintained, the electrons move in the magnetic field in a circular path of radius 1.14 cm. Determine the ratio of the electronic charge to the electron mass if E = 8.00 kV/ m and the magnetic field has flux density 2.00 mT.
Homework Equations
F=(q)(v)(b)*sin(theta)
F=(m(v)^2)/R
F=q*e
The Attempt at a Solution
The magnetic force must be equal to the centripetal force; thus...
q*v*b*sin(90)=((m)(v)^2)/r
-->q/m=v/(r*B)
If I have velocity, I'll be able to solve this problem. I'm not sure how the electric field ties into all of this; my gut tells me that I need to use it to solve for the velocity, but I have no clue how. Some additional work has been attached. Any tips are appreciated.