- #1
Psywing
- 5
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Hello, everyone.
Now, I recently did an experiment in school to determine the Specific Heat Capacity of rubber using a calorimeter. We're using the mixing method to figure it out.
The mass of the calorimeter, rubber and water was measured. And the S.H.C is already known for the water and calorimeter. The temperatures are as follows:
Temp. of cold water = 26°C
Temp. of hot object = 95°C
Temp. of mixture = 32°C
Mo co θo = Mc cc θc + Mw cw θw
0 = object
c = calorimeter
w = water
The problem I'm having is finding the temp. change. This is what I did.
To find the temp. change of the rubber = 26 + 32 = 58. And from that 95 - 58 = 37.
To find the temp. change of the calorimeter = 95 - 32 = 63.
To find the temp. change of the water = 95 - 26.
I'd like to know if this is accurate because, when I do the calculations I get a really weird figure for the S.H.C of the rubber.
Homework Statement
Now, I recently did an experiment in school to determine the Specific Heat Capacity of rubber using a calorimeter. We're using the mixing method to figure it out.
The mass of the calorimeter, rubber and water was measured. And the S.H.C is already known for the water and calorimeter. The temperatures are as follows:
Temp. of cold water = 26°C
Temp. of hot object = 95°C
Temp. of mixture = 32°C
Homework Equations
Mo co θo = Mc cc θc + Mw cw θw
0 = object
c = calorimeter
w = water
The Attempt at a Solution
The problem I'm having is finding the temp. change. This is what I did.
To find the temp. change of the rubber = 26 + 32 = 58. And from that 95 - 58 = 37.
To find the temp. change of the calorimeter = 95 - 32 = 63.
To find the temp. change of the water = 95 - 26.
I'd like to know if this is accurate because, when I do the calculations I get a really weird figure for the S.H.C of the rubber.