- #1
willr12
- 17
- 2
okay...if you accept that the sequence
1+2+3+4...=-1/12,
I think I have determined a finite value of infinity.
To find the value of the sums of all natural numbers up to a number, you can use the equation
((x^2)+x)/2.
An example would be 4.
4+3+2+1=10.
((4^2)+4)/2 also equals 10.
following this logic,
((x^2)+x)/2=-1/12
is true for the above sequence. this can be rearranged to
(x^2)+x+1/6
This is the resulting quadratic equation. Using the quadratic formula, one obtains the x intercepts as
(-3+-(sqrt3))/6.
and since x is infinity in this situation (since the highest value is infinity), the x intercepts are the values of infinity in the equation. Therefore, by assigning a value of -1/12 to riemann zeta(-1), you also assign finite values to infinity, approximately
-0.211324...
and
-0.788675...
If there is any faulty reasoning, please remember I'm 15 and I most likely have no clue what I'm talking about.
1+2+3+4...=-1/12,
I think I have determined a finite value of infinity.
To find the value of the sums of all natural numbers up to a number, you can use the equation
((x^2)+x)/2.
An example would be 4.
4+3+2+1=10.
((4^2)+4)/2 also equals 10.
following this logic,
((x^2)+x)/2=-1/12
is true for the above sequence. this can be rearranged to
(x^2)+x+1/6
This is the resulting quadratic equation. Using the quadratic formula, one obtains the x intercepts as
(-3+-(sqrt3))/6.
and since x is infinity in this situation (since the highest value is infinity), the x intercepts are the values of infinity in the equation. Therefore, by assigning a value of -1/12 to riemann zeta(-1), you also assign finite values to infinity, approximately
-0.211324...
and
-0.788675...
If there is any faulty reasoning, please remember I'm 15 and I most likely have no clue what I'm talking about.