Determining Basic and Free Variables in a Linear System

In summary, the system of equations can be simplified to the augmented matrix form and then transformed into row echelon form using fundamental row operations. The correct result is shown above, and to determine the basic and free variables, one can refer to a basic guide on the topic.
  • #1
amcgl064
2
0
Find the general solution to the following system of equations and indicate which variables are free and which are basic.

png.latex

png.latex

png.latex


Putting it in augmented matrix form to start we have:
1 -1 -1 4 | -3
1 0 -1/2 3 | -1
1 1 0 2 | 1

Now performing the following fundamental row operations:

R1<-->R2
R2+R3-->R2
-2R3+R2-->R2
-R3+R1-->R3
R2/-2
R2+R3-->R2
-3R3+R1-->R1

And finally I end with the augmented matrix:

1 0 -2 0 | 5
0 1 0 0 | 0
0 0 -1/2 1 |-2

Can someone please tell me if I got the correct matrix at the end and if so how do I determine which variables are free and which are basic?

Thank you.
 
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  • #2
amcgl064 said:
Find the general solution to the following system of equations and indicate which variables are free and which are basic.

png.latex

png.latex

png.latex


Putting it in augmented matrix form to start we have:
1 -1 -1 4 | -3
1 0 -1/2 3 | -1
1 1 0 2 | 1

Now performing the following fundamental row operations:

R1<-->R2
R2+R3-->R2
-2R3+R2-->R2
-R3+R1-->R3
R2/-2
R2+R3-->R2
-3R3+R1-->R1

And finally I end with the augmented matrix:

1 0 -2 0 | 5
0 1 0 0 | 0
0 0 -1/2 1 |-2

Can someone please tell me if I got the correct matrix at the end and if so how do I determine which variables are free and which are basic?

Thank you.

Hi amcgl064, :)

The answer you have obtained for the row echelon form is incorrect. The correct answer is,

\[\left(\begin{matrix}1&-1&-1&4\\0&1&\frac{1}{2}&-1\\0&0&0&0\end{matrix}\right)\]

Please refer >>this<< for a basic introduction about basic variables and free variables. I hope you can do the rest. :)

Kind Regards,
Sudharaka.
 

FAQ: Determining Basic and Free Variables in a Linear System

What is a linear system?

A linear system is a set of equations that involve two or more variables, where the equations are linear (meaning they can be written in the form of y = mx + b). The goal of solving a linear system is to find the values of the variables that make all of the equations true simultaneously.

How do I solve a linear system?

There are several methods for solving a linear system, including substitution, elimination, and graphing. The most commonly used method is elimination, where you manipulate the equations to eliminate one of the variables, and then solve for the remaining variable. This process is repeated until all variables have been solved for, resulting in a unique solution to the system.

What is a unique solution?

A unique solution to a linear system means that there is only one set of values for the variables that make all of the equations true. This is typically represented as an ordered pair (x, y) or a coordinate on a graph. If there are multiple solutions or no solutions, the system is considered inconsistent.

Can I use a calculator to solve a linear system?

Yes, there are many calculators and computer programs that can solve linear systems for you. However, it is important to understand the steps and concepts behind solving a linear system, as well as how to check your answer, rather than relying solely on technology.

Why is solving linear systems important?

Solving linear systems is a fundamental skill in mathematics and is used in many real-world applications. It allows us to find the relationship between variables and make predictions or solve problems. For example, linear systems are commonly used in economics, engineering, and science to model and analyze various situations.

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