Larrytsai said:5.82g of a Hydrate is taken. If 62.9% of H2O is contained in the Hydrate what is the mass of the anhydrous salt?
so far i got 62.9% and 37.1% and i was thinking about getting H2O in grams but i don't know how
Snazzy said:Well, if you multiply 0.371 by 5.82, I believe that would give you the mass of the anhydrous salt since 0.629 x 5.82 is the mass of the water contained in the hydrate.
The mass of a hydrate can be calculated by taking the mass of the hydrate after it has been dried and subtracting the mass of the anhydrous compound. This will give you the mass of the water in the hydrate. Then, divide this mass by the mass of the anhydrous compound and multiply by 100 to get the percent composition of water in the hydrate. Finally, multiply this percent by the total mass of the hydrate to get the mass of water in the sample.
To determine the mass of a hydrate, you will need a balance to measure the mass of the sample, a crucible and lid to hold the sample, and a Bunsen burner or other heat source to dry the sample. You may also need a desiccator to keep the sample dry before weighing.
The heating time may vary depending on the sample and the heat source used. Generally, the sample should be heated until it turns a constant color or until the sample stops losing mass. This indicates that all of the water has been driven off and the sample is completely dry.
No, the mass of a hydrate cannot be accurately determined without heating it. The purpose of heating is to drive off the water and determine the mass of the anhydrous compound. Without heating, the mass of the water cannot be separated from the total mass of the sample.
Some factors that could affect the accuracy of your mass determination include not heating the sample for long enough, not using a properly calibrated balance, and not properly sealing the crucible and lid to prevent water from escaping during heating. Additionally, any impurities in the sample or loss of sample during handling can also affect the accuracy of the mass determination.