Determining Electric and Magnetic Fields: An Electron's Journey

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An electron with a velocity of 1.2 * 10^4 m/s in the positive x direction and an acceleration of 2 * 10^12 m/s^2 in the positive z direction is analyzed within a uniform electric field of 20 N/C. To determine the magnetic field, the force equation F = qE + qv x B is applied, requiring knowledge of the force acting on the electron. Newton's second law, F = ma, is relevant for calculating the force, but the x-component of the magnetic field can be any negative value, leading to confusion. It is clarified that when crossing two parallel directions, such as velocity in the x-direction with a magnetic field also in the x-direction, the result is zero. Thus, the x-component of the magnetic field does not affect the electron's motion in this scenario.
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Homework Statement



An electron has a velocity of 1.2 * 10^4 m/s ( in the positive x direction ), and an acceleration of 2 * 10 ^ 12 m/s^2 ( in the positive z direction ) in a uniform electric and magnetic field. If the electric field has a magnitude of 20 N/C ( in the positive z direction), what can you determind about the magnetic field in the region? what can you not determine?

Homework Equations



F = qE + qv x B

The Attempt at a Solution



I need the force quantity to figure out the problem, but am lost besides this. Can someone offer a little help. Thanks.
 
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You are given the acceleration and the mass of an electron is something you can easily look up.
 
Ok I was thinking I was going to be using Newton's second law, but wan't sure. I have the answers to the problem and for the x- vector it says it can be any negative value, can anyone explain why this is?
 
Well you do need to use Newton's 2nd law since F = ma to use the left hand side of your equation. As far as the x-direction of the magnetic field is concerned, what happens when you cross a velocity, that is in the x-direction, with a field in the x-direction? Matter of fact, what happens when you cross any 2 parallel directions together?
 
It would be zero not any negative value correct?

Thanks for all of the help.
 
Yes, any x-component, negative or positive, crossed into the velocity would give 0 here.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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