- #1
Moose100
- 116
- 0
Homework Statement
The Heat of combustion of Ethane is 373 kcal/mole. Assuming that 60% of the heat is useful , how many liters of ethane,, measured at standard temperature and pressure, must be burned to convert 50.0kg of water ar 10.0C to steam at 100.0C? One mole of a gas occupies 22.4 liters at precisely 0C and 1atm.
Homework Equations
PV=nRT Q=mcΔT
The Attempt at a Solution
Qburned=Q heat up
=mL + mcΔT
540g/C(50g)+ 50(1cal/gC)(100-10)
Q=31500 cal
n= Q/heat of combustion(60%)
n=0.1407mol
PV=nRT
V=0.1407mol(8314j/kmolK)(273K)/1atm
V=3193680 L
The book has it at 315000. Is there something wrong here? I feel like I am missing a term or left something out?