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Homework Statement
When a certain metallic surface is illuminated with electromagnetic radiation of wavelength λ
max kinetic energy of photoelectrons is 40.5 eV. On same surface infrared radiation of 3λ, the ma kinetic energy is 5% less than that of incident radiation. Determine the maximum wavelength of incident radiation on this surface that will cause photo-emission to occur.
Homework Equations
Kmax = hc/λ + ∅
[λ][/c] = hc/∅
The Attempt at a Solution
okay, for wavelength λ I said that
∅= Kmax - hc/λ = 40.5 eV - 1240eV / λ
then for wavelength 3λ
∅= 38.475eV - 1240eV/ 3λ
Now, I want to plug in these values obtained for the work function ∅ into the Max wavelength equation (or cutoff wavelength equation) , but since I have two values what do I do?
Is this the write route
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