- #1
karush
Gold Member
MHB
- 3,269
- 5
Find the equation of the curve that passes through the point\(\displaystyle (1,2)\)
and has a slope of $\displaystyle\left( 3+\frac{1}{x}\right)$
at any point \(\displaystyle (x,y)\) on the curve.
$(A) 2xe^{3x-3}$
$(B) 2xe^{3x+3}$
$(C) 2xe^3$
$(D) 2e^{3x-3}$
\(\displaystyle A(1)=2\) and \(\displaystyle D(1)=2 \)
so \(\displaystyle B\) and \(\displaystyle C\) are out.
the answer is\(\displaystyle (A)\) but I took \(\displaystyle A'\) and \(\displaystyle D' \)but couldn't equate that to
$\displaystyle\left( 3+\frac{1}{x}\right)$
and has a slope of $\displaystyle\left( 3+\frac{1}{x}\right)$
at any point \(\displaystyle (x,y)\) on the curve.
$(A) 2xe^{3x-3}$
$(B) 2xe^{3x+3}$
$(C) 2xe^3$
$(D) 2e^{3x-3}$
\(\displaystyle A(1)=2\) and \(\displaystyle D(1)=2 \)
so \(\displaystyle B\) and \(\displaystyle C\) are out.
the answer is\(\displaystyle (A)\) but I took \(\displaystyle A'\) and \(\displaystyle D' \)but couldn't equate that to
$\displaystyle\left( 3+\frac{1}{x}\right)$