- #1
flyingpig
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Homework Statement
[PLAIN]http://img97.imageshack.us/img97/6749/kappam.jpg
Homework Equations
U = (1/2)CV2
V = V0/k
The Attempt at a Solution
(1) [tex]\Delta V_0= \Delta V[/tex] <==== Electrical potential difference is constant since the battery was never removed.
(2) [tex]\kappa Q_0 = Q[/tex] <=== Since the battery is NOT removed and therefore the potential difference must rema
Divide (2) by (1) and I get
[tex]\kappa C_0 = C[/tex]
[tex]U_0 = \frac{1}{2}C_0\Delta V_0^2[/tex]
Now then the only change is the capacitance and so we have
[tex]U = \frac{1}{2}C\Delta V_0^2[/tex]
[tex]U = \frac{1}{2}(\kappa C_0){\Delta V_0^2}[/tex]
Pull out kappa and we get
[tex]U = \kappa \frac{1}{2}C_0\Delta V_0^2[/tex]
Which should be recognized as U = κU0For part b) is the question already been answered? That is κQ0 = Q
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