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thatguy4000
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Homework Statement
A. Two identical speakers, with the same phase constant, are arranged along a 1D track. One speaker remains at the origin. The other speaker can slide along the track to any position x. You are on the track at x=10 m. You hear interference maxima when the adjutable speaker's position is 0.6 m and 1.2 m and at no points in between. What is the frequency of the sound from the speakers in Hz?
B. The speakers are now allowed to have different phase constants. They are adjusted so that you hear interference maxima when the adjustable speaker is at x = 0.6 m and again when it is at x = 1.05 m. What is the difference in the phase constant between the two speakers in rad?
Homework Equations
velocity = wavelength * frequency
delta phi = phi2 - phi1 = (2pi * delta x)/wavelength
The Attempt at a Solution
The wavelength in part A would be 0.6m because that's the distance between the maximum interference, giving me frequency = 343m/s / 0.6m = 571.67Hz (correct).
I could not get B correctly though. Using the difference in phase constant equation, delta phi (phase difference) = (2pi * 0.45m) / 0.6m = 4.71 radians (wrong). What did I do wrong?