"Different" energy eigenstates - clarification of meaning?

In summary, Gerard 't Hooft discusses the interference patterns observed in the double slit experiment and how the initial state of the fast variables must now be described as a superposition of different energy eigenstates. He argues that all so called "fast variables" must be in their ground state and that the excited modes of the fast variables are only virtually present.
  • #1
asimov42
378
4
Apologies for an additional thread (could not delete the previous one which was not coherent). After reading this paper:

https://link.springer.com/article/10.1007/s10701-021-00464-7
"Fast Vacuum Fluctuations and the Emergence of Quantum Mechanics" Gerard ’t Hooft

I was struck by a general question - the paper states (in relation to interference in the double slit experiment that): "It does something else however: if we select one slit, and repeat this experiment many times, then we are making a selection among the initial states chosen for the fast variables. This selection will not be an even one! Therefore, the initial state of the fast variables must now be described as a superposition of different energy eigenstates."

't Hooft's formulation requires all so called "fast variables" to be in their ground state always (as far as I can tell). So my question is: what does it mean to have "different" energy eigenstates when all variables must be in their lowest-energy eigenstates? This is a more general question that is not specific to this paper. That is, what's different?

Are two energy eigenstates considered "different" if they differ by phase only? Or can variables with different energy eigenstates have the same energy but be distinguished by other aspects of the state that may be different? I am confused in general about how two variables can be in their lowest energy states and yet be "different."
 
Last edited:
Physics news on Phys.org
  • #2
I should have been more careful, I meant the Hamiltonian - from the paper: "Therefore, the initial state of the fast variables must now be described as a superposition of different energy eigenstates."

My understanding was that only one energy eigenstate was allowed in this case, in which all the fast variables have their lowest energy. Hence the superposition mentioned above confuses me.

Also, in a related paper 't Hooft mentions that "the excited modes [of the fast variables] are only virtually present."

Since the excited modes of the fast variables are forbidden by energy conservation, what does a 'virtual state' mean in the context above?
 

FAQ: "Different" energy eigenstates - clarification of meaning?

What are energy eigenstates in quantum mechanics?

Energy eigenstates are specific states of a quantum system that have a definite energy. These states are solutions to the Schrödinger equation, where the Hamiltonian operator (which represents the total energy of the system) acts on the eigenstate and returns the same state multiplied by a constant (the energy eigenvalue).

How do energy eigenstates differ from other quantum states?

Energy eigenstates are special because they have a well-defined energy, meaning that if you measure the energy of the system while it is in this state, you will always get the same value. In contrast, other quantum states may be superpositions of multiple energy eigenstates and do not have a definite energy.

What is the significance of different energy eigenstates?

Different energy eigenstates correspond to different energy levels of the quantum system. These levels are crucial for understanding phenomena such as atomic spectra, molecular vibrations, and quantum transitions. Each energy eigenstate represents a unique configuration of the system with a specific energy.

Can a quantum system be in a superposition of different energy eigenstates?

Yes, a quantum system can be in a superposition of different energy eigenstates. This means that the system does not have a definite energy but rather a probability distribution over several possible energies. When measured, the system will collapse into one of the energy eigenstates, yielding a specific energy value.

How are energy eigenstates related to the time evolution of a quantum system?

The time evolution of a quantum system is governed by the Schrödinger equation. If the system is in an energy eigenstate, its time evolution is relatively simple: the state acquires a phase factor that evolves linearly with time. For a superposition of energy eigenstates, each component evolves with its own phase factor, leading to more complex time-dependent behavior.

Back
Top