- #1
Ara macao
- 27
- 0
Let f(x) = x if x rational and f(x) = 0 if x is irrational
Let g(x) = x^2 if x rational and g(x) = 0 if x is irrational.
Both functions are continuous at 0 and discontinuous at each x != 0.
How do I show that f is not differentiable at 0?
How should I show that g is differentiable at 0? Give g'(0) as well.
Thanks...
Let g(x) = x^2 if x rational and g(x) = 0 if x is irrational.
Both functions are continuous at 0 and discontinuous at each x != 0.
How do I show that f is not differentiable at 0?
How should I show that g is differentiable at 0? Give g'(0) as well.
Thanks...