Differential Amplifier Equations for Vout Determination | Amplifier-1.jpg

In summary: So I'm glad that I could help a little. Take care!In summary, the amplifier has four nodes, V1-V4. V1 and V4 are at the same potential, V2-V3 are not. Current flows from right to left on the wire connected to Vo and from left to right on the wire connected to I. The voltage on V3 and V4 is the same as VA and VB, respectively. VA and VB are not zero volts. There is negative feedback, so V4=V3.
  • #1
esmeco
144
0
Hello!
I'm trying to determine Vout on this amplifier and I'm having some problems with the equations,because I'm not sure if they're correct!
This's the link to the amplifier:

http://i75.photobucket.com/albums/i281/esmeco/Amplifier-1.jpg

The equations I've got so far are these:

IB=0
IA=0
V2-V3=R3xI3
V3-0=I4xR4
V4-V1=R1xI1
Vo-V4=R2xI2

I have some questions:how do I know from which way does the current flow(On the wire that is connected to Vo I've determined that current flows from right to left,and,on the top,the current flows from left to right)?Is the voltage on node V3 and V4 the same as VA and VB respectively(As Va=Vb the voltage in both points are 0 volts)?
Any help on this is really appreciated!
Thanks in advance!:smile:
 
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  • #2
esmeco said:
Hello!
I'm trying to determine Vout on this amplifier and I'm having some problems with the equations,because I'm not sure if they're correct!
This's the link to the amplifier:

http://i75.photobucket.com/albums/i281/esmeco/Amplifier-1.jpg

The equations I've got so far are these:

IB=0
IA=0
V2-V3=R3xI3
V3-0=I4xR4
V4-V1=R1xI1
Vo-V4=R2xI2

I have some questions:how do I know from which way does the current flow(On the wire that is connected to Vo I've determined that current flows from right to left,and,on the top,the current flows from left to right)?Is the voltage on node V3 and V4 the same as VA and VB respectively(As Va=Vb the voltage in both points are 0 volts)?
Any help on this is really appreciated!
Thanks in advance!:smile:

When you are using the ideal op amp assumptions (for quick circuit analysis), you assume:
[tex] i_{+} = i_{-} = 0 [/tex]
[tex] v_{+} = v_{-} [/tex]

Thus the node you labeled V4 is at the same potential as V3.

Write the KCL equations for the current flowing into the nodes.
 
  • #3
Oh, and VA and VB are not zero volts. You have not grounded either of them.
 
  • #4
So,since there is negative feedback,V4=V3,but would not they be equal to 0?JUSt another question:if there wasn't a resistor connected to V4,would V4 be equal to V1 and thus V3 equal to V1 and the current that would flow from V4 to V1 equal to 0?
 
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  • #5
esmeco said:
So,since there is negative feedback,V4=V3,but would not they be equal to 0?JUSt another question:if there wasn't a resistor connected to V4,would V4 be equal to V1 and thus V3 equal to V1 and the current that would flow from V4 to V1 equal to 0?

So,since there is negative feedback,V4=V3,but would not they be equal to 0?

No.

V4 = V3, because that is an assumption you make. When you are working with an ideal op-amp model.

I pulled this from http://en.wikipedia.org/wiki/Operational_amplifier" ,
"For any input voltages the ideal op-amp has infinite open-loop gain, infinite bandwidth, infinite input impedances resulting in zero input currents, infinite slew rate, zero output impedance and zero noise."

So you assume infinite open-loop gain.
A differential amplifier the output is equal to [itex] A(v_+-v_-) [/itex].

Ideally, the voltage between the terminals is zero, thus:
[tex] A(v_+-v_-)=v_0 [/tex]
[tex] A(0) = v_0 [/tex]
[tex] 0 = \frac{v_0}{A} [/tex]

Since A is infinite, v- must equal v+.

Is the fact that there is zero current flowing into the op-amp messing with you? Why do you think V3 = V4 = 0?

Zero current into the op-amp essentially means you can take the op amp out of there, since it acts as an open circuit. For example on the bottom you would have,

V1-----R1------V4-------R2-------V0

and on the top you would have,

V2-----R3------V3-------R4------GROUND

Now since you are using ideal op amp assumption, V3 = V4, so you get a system of equations:
V1-----R1------VN-------R2-------V0
V2-----R3------VN-------R4------GROUND


For your second question,
if there wasn't a resistor connected to V4,would V4 be equal to V1 and thus V3 equal to V1 and the current that would flow from V4 to V1 equal to 0?

What do you mean if there wasn't a resistor connected to V4. You have R1, and R2 connected to V4. Which one are you talking about?
 
Last edited by a moderator:
  • #6
Thanks for the explanations!I'm now understanding this...Well,when I said about a resistor not connected to V4 I meant R1,and in that situation would V4=V1?
 
  • #7
esmeco said:
Thanks for the explanations!I'm now understanding this...Well,when I said about a resistor not connected to V4 I meant R1,and in that situation would V4=V1?

If you remove node 1 (short it for example), yup, V4 would equal V1.

And no problem at all man. I actually have a test on Wednesday about this stuff (it's for the first class after basic circuit analysis though).
 

FAQ: Differential Amplifier Equations for Vout Determination | Amplifier-1.jpg

What is a differential amplifier?

A differential amplifier is an electronic circuit that amplifies the difference between two input signals while rejecting any common-mode signals that are present in both inputs. It is commonly used in analog circuits to increase the gain, accuracy, and dynamic range of signals.

What is the purpose of a differential amplifier?

The purpose of a differential amplifier is to amplify small signals that are present in noisy environments. By amplifying the difference between two signals, it effectively cancels out any noise that is present in both inputs, resulting in a cleaner and more accurate output signal.

How does a differential amplifier work?

A differential amplifier works by comparing the voltage levels of two input signals and amplifying the difference between them. This is achieved by using a combination of transistors and resistors in a configuration known as a "long-tailed pair". The output of the amplifier is determined by the difference in voltage between the two inputs.

What are the advantages of using a differential amplifier?

The main advantages of using a differential amplifier include high gain, high common-mode rejection ratio (CMRR), and low distortion. It also has a wide bandwidth and is less sensitive to temperature changes, making it a reliable choice for amplifying small signals in various applications.

What are the applications of differential amplifiers?

Differential amplifiers are commonly used in audio amplifiers, instrumentation amplifiers, and operational amplifiers. They are also used in communication systems, control systems, and signal processing applications. Additionally, they are used in medical equipment, such as ECG machines, to amplify small biological signals.

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