- #1
TranscendArcu
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Homework Statement
Solve the differential equation: [itex]\frac{dy}{dx} = cos^2 (x) cos^2 (2y)[/itex]
The Attempt at a Solution
I rewrote the equation
[itex]\frac{dy}{cos^2 (2y)} = sec^2 (2y) = cos^2 (x) dx[/itex]. Then I integrated,
[itex]\frac{tan(2y)}{2} = \frac{1}{2} (x + sin(x)cos(x)) + c[/itex]. Then I solved for y,
[itex]y = \frac{tan^{-1} (x + sin(x)cos(x) + c)}{2}[/itex]
But this isn't the answer my book gives (or at least it doesn't look very similar). Where did I go wrong?