- #1
iVenky
- 212
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Consider a circle of radius 'a' and centre (h,b)
then the equation of the circle is given by (x-h)2 + (y-b)2 = a2
I expressed this in terms of differential equations which is -
a= {[1+(dy/dx)2]3/2}/{d2y/dx2}
According to my book - this equation indicates that 'a' is a constant. How can you infer from this equation that 'a' is a constant? (Note: I know that 'a' is a constant but I can't understand how you can infer that from this differential equation).
Thanks in advance.
then the equation of the circle is given by (x-h)2 + (y-b)2 = a2
I expressed this in terms of differential equations which is -
a= {[1+(dy/dx)2]3/2}/{d2y/dx2}
According to my book - this equation indicates that 'a' is a constant. How can you infer from this equation that 'a' is a constant? (Note: I know that 'a' is a constant but I can't understand how you can infer that from this differential equation).
Thanks in advance.
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