Differential Equations and Substitutions (Calc 2)

In summary: Now, use the chain rule to find this derivative.In summary, to solve the differential equation xy' = y + xe^(y/x) using the substitution v=(y/x), we need to make the change of variable with the differential too and write dy/dx in terms of x and v. This can be done by recognizing that y=v(x)·x, and using the chain rule to find dy/dx. From there, we can substitute v=(y/x) and solve for dv/dx, which will lead us to a separable differential equation in terms of v and x.
  • #1
lelandsthename
12
0

Homework Statement


Solve xy' = y + xe^(y/x) using the substitution v=(y/x)


Homework Equations


Solving differential equations, substitution


The Attempt at a Solution


x (dy/dx) = y + xe^(y/x)

(dy/dx) = (y/x) + e^(y/x)

Substituting v=(y/x)

(dy/dx) = v + e^(v)

I do not know how to proceed from here. (There are so many variables that aren't x and y! Ahh) Any guidance would be greatly appreciated!
 
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  • #2
You need to make the change of variable with the differential too. In other words you need to write

[tex]\frac{dy}{dx}[/tex]

In terms of x and v. Note that v=v(x), that is, v is a function of x.
 
  • #3
If v=y/x, then y= ??

and from that dy/dx= ??
 
  • #4
Hmm, ok, so dv = dy/dx? Somehow I still think I'm missing something. Shouldn't there be a dv/dx somewhere or something? I am just not seeing it =/
 
  • #5
lelandsthename said:
Hmm, ok, so dv = dy/dx? Somehow I still think I'm missing something. Shouldn't there be a dv/dx somewhere or something? I am just not seeing it =/
You're on the right lines, but not quite there. As Halls says,

[tex]y = v(x)\cdot x[/tex]

Now you need to find the first derivative of the above function with respect to x,

[tex]\frac{dy}{dx} =\ldots[/tex]
 

FAQ: Differential Equations and Substitutions (Calc 2)

1) What is a differential equation?

A differential equation is a mathematical equation that relates a function with its derivatives. It is used to model a wide range of physical phenomena and is an important tool in many scientific fields.

2) What is a substitution in calculus?

In calculus, a substitution is the process of replacing a variable in an equation with a new variable or expression. This can make it easier to solve the equation or integrate a function.

3) How do you solve a differential equation using substitution?

To solve a differential equation using substitution, you first need to identify the type of equation (e.g. separable, exact, etc.) and then choose an appropriate substitution that will simplify the equation. You then solve the resulting equation and substitute back in the original variable to find the solution.

4) Can substitution be used for all types of differential equations?

No, substitution is only applicable for certain types of differential equations, such as separable and exact equations. Other methods, such as using an integrating factor or Laplace transform, may be needed for more complex equations.

5) Why is it important to learn about differential equations and substitutions?

Differential equations and substitutions are essential tools in many scientific fields, including physics, engineering, and economics. They allow us to model and understand real-world systems and make predictions about their behavior. Additionally, many advanced mathematical concepts and techniques are built upon the foundation of differential equations and substitutions.

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