- #1
mathi85
- 41
- 0
Hi!
I would like to ask anyone with some spare time to check my assignment questions. Last time I was asked to post one task at a time so I will.
Thank you in advance for your time.
Task 2:
Determine the equation of the curve which satisfies the differential equation:
2xy(dy/dx)=x2+1
and which passes through the point (1, 2)
Solution:
2xy(dy/dx)=x2+1 /:2x
y(dy/dx)=(x2+1)/(2x)
y(dy/dx)=(1/2)[(x2+1)/x]
∫ y dy=(1/2)∫ x+(1/x) dx
(1/2)y2=(1/2)(lnx+(1/2)x2)+c
General Solution
(1/2)y2=(1/2)lnx+(1/4)x2+c
x=1 when y=2
∴(1/2)(2)2=(1/2)ln(1)+(1/4)(1)2+c
∴c=7/4
Particular Solution:
(1/2)y2=(1/2)lnx+(1/4)x2+7/4
∴y=√[lnx+x2/2+3.5]
I would like to ask anyone with some spare time to check my assignment questions. Last time I was asked to post one task at a time so I will.
Thank you in advance for your time.
Task 2:
Determine the equation of the curve which satisfies the differential equation:
2xy(dy/dx)=x2+1
and which passes through the point (1, 2)
Solution:
2xy(dy/dx)=x2+1 /:2x
y(dy/dx)=(x2+1)/(2x)
y(dy/dx)=(1/2)[(x2+1)/x]
∫ y dy=(1/2)∫ x+(1/x) dx
(1/2)y2=(1/2)(lnx+(1/2)x2)+c
General Solution
(1/2)y2=(1/2)lnx+(1/4)x2+c
x=1 when y=2
∴(1/2)(2)2=(1/2)ln(1)+(1/4)(1)2+c
∴c=7/4
Particular Solution:
(1/2)y2=(1/2)lnx+(1/4)x2+7/4
∴y=√[lnx+x2/2+3.5]