MHB Differential Equations by separation of variables

LAK
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Can someone please help me to calculate the following using separation of variables:

dy/dx = x*(1 - y^2)^(1/2)

to that the solution is in the form:

y =
 
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I have moved both your threads here to the Differential Equations subforum as this is a better fit for them.

What do you get when you separate the variables, before integrating?
 
LAK said:
Can someone please help me to calculate the following using separation of variables:

dy/dx = x*(1 - y^2)^(1/2)

to that the solution is in the form:

y =

For starters:

$\displaystyle \begin{align*} \frac{1}{\sqrt{1 - y^2}} \, \frac{dy}{dx} = x \end{align*}$

and now you can integrate both side w.r.t. x :)
 
There is the following linear Volterra equation of the second kind $$ y(x)+\int_{0}^{x} K(x-s) y(s)\,{\rm d}s = 1 $$ with kernel $$ K(x-s) = 1 - 4 \sum_{n=1}^{\infty} \dfrac{1}{\lambda_n^2} e^{-\beta \lambda_n^2 (x-s)} $$ where $y(0)=1$, $\beta>0$ and $\lambda_n$ is the $n$-th positive root of the equation $J_0(x)=0$ (here $n$ is a natural number that numbers these positive roots in the order of increasing their values), $J_0(x)$ is the Bessel function of the first kind of zero order. I...
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