Differential Equations - Initial Value Problem

[mattbonner]

Homework Statement

Suppose that the initial value problem
y' = 7(x^2) + (5y^2) − 6, y(0)=−2
has a solution in an interval about x=0.

Find y'(0) =
Find y''(0) =
Find y'''(0) =

Homework Equations

get it into standard form: dy/dt + p(t)y = g(t)
find integrating factor = e^($$\int$$p(t)dt + k

multiply everything by integrating factor, simplify left-hand-side and then integrate both sides

using initial condition, solve for C
solve for y

The Attempt at a Solution

i don't seem to be able to get it into standard form

i tried doing y' - 5y^2 = 7x^2 -6
which gave me an integrating factor of e^-5xy

i tried following the rest of the steps with that integrating factor but its not working

 

[Dick]

You don't actually have to solve the equation to find the derivatives of y(x) at x=0. To find y'(0) just plug x=0, y=(-2) into the equation. To find the higher derivatives, just differentiate the equation with respect to x a couple of times.

 

[mattbonner]

oh wow i feel like such a moron
thank you so much!

edit: wait, for y''(0)

i differentiated it, and i got 14x?edit(2): nvm i solved it