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BigJon
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Homework Statement
a heavy object of mass m is suspened in a room through a linear spring whose spring constant is k. Initially the object is suspported so that the spring is at its free length (neither strecthed/compressed) which is take to be x=0. At time zero the support is removed and theobject is allowed to oscillatee under the combined influence of both gravity and spring forces. Using Newtons second law of motion obtain the differential equation that describes the position x of the mass m relative to the undistrubed endpoint of the spring as a funtion of time
Homework Equations
F=ma,F=-mg,F=-kx
The Attempt at a Solution
So what is did was F=ma, F=-mg, F=-kx
a=d^2s/dt^2, F=ma=-kx=-mg so,
-kx-mg=m(d^2s/dt^2) solved for d^2s/dt^2 and got d^2s/dt^2=-(kx/m)-g
I don't have any idea if that is correct or not